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sin 15 0 ∘ + tan 31 5 ∘ − cos 24 0 ∘ = …

 

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S. Nur

Master Teacher

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 sin space 150 degree plus tan space 315 degree minus cos space 240 degree equals 0.

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Dengan demikian, .

table attributes columnalign right center left columnspacing 0px end attributes row cell sin space 150 degree end cell equals cell sin open parentheses 180 degree minus 30 degree close parentheses end cell row blank equals cell sin space 30 degree end cell row blank equals cell 1 half end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell tan space 315 degree end cell equals cell tan space open parentheses 360 minus 45 degree close parentheses end cell row blank equals cell negative tan space 45 degree end cell row blank equals cell negative 1 end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell cos space 240 degree end cell equals cell cos space open parentheses 270 degree minus 30 degree close parentheses end cell row blank equals cell negative sin space 30 degree end cell row blank equals cell negative 1 half end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell sin space 150 degree plus tan space 315 degree minus cos space 240 degree end cell equals cell 1 half minus 1 minus open parentheses negative 1 half close parentheses end cell row blank equals cell 1 half minus 1 plus 1 half end cell row blank equals cell 1 minus 1 end cell row blank equals 0 end table 

Dengan demikian, sin space 150 degree plus tan space 315 degree minus cos space 240 degree equals 0.

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