Roboguru

Pertanyaan

begin mathsize 14px style stack L i m with x rightwards arrow infinity below open parentheses fraction numerator 2 x over denominator 3 minus square root of 9 minus x end root end fraction close parentheses equals.... end style 

Pembahasan Soal:

Dari bentuk limit didapat:

begin mathsize 14px style stack L i m with x rightwards arrow infinity below open parentheses fraction numerator 2 x over denominator 3 minus square root of 9 minus x end root end fraction close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open parentheses dikali space sekawan close parentheses equals stack L i m with x rightwards arrow infinity below open parentheses fraction numerator 2 x over denominator 3 minus square root of 9 minus x end root end fraction close parentheses open parentheses fraction numerator 3 plus square root of 9 minus x end root over denominator 3 plus square root of 9 minus x end root end fraction close parentheses equals stack L i m with x rightwards arrow infinity below open parentheses fraction numerator 2 x left parenthesis 3 plus square root of 9 minus x end root right parenthesis over denominator 9 minus left parenthesis 9 minus x right parenthesis end fraction close parentheses equals stack L i m with x rightwards arrow infinity below open parentheses fraction numerator 2 x left parenthesis 3 plus square root of 9 minus x end root right parenthesis over denominator x end fraction close parentheses equals stack L i m with x rightwards arrow infinity below 2 left parenthesis 3 plus square root of 9 minus x end root right parenthesis equals infinity end style 

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Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Maret 2021

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