Iklan

Iklan

Pertanyaan

( 2 1 ​ ) 4 a 4 b − 5 2 − 3 a 3 b − 4 ​ = ...

  1. 2 a b

  2. fraction numerator 2 a over denominator b end fraction

  3. fraction numerator a b over denominator 2 end fraction

  4. fraction numerator b over denominator 2 a end fraction

  5. fraction numerator 2 b over denominator a end fraction

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Iklan

Pembahasan

Pembahasan
lock

Ingat kembali: sehingga diperoleh perhitungan: Dengan demikian, nilai dari adalah . Jadi, jawaban yang tepat adalah E.

Ingat kembali:

a to the power of m over a to the power of n equals a to the power of m minus n end exponent comma space a not equal to 0  

1 over a to the power of n equals a to the power of negative n end exponent comma space a not equal to 0

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent

sehingga diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 2 to the power of negative 3 end exponent a cubed b to the power of negative 4 end exponent over denominator open parentheses begin display style 1 half end style close parentheses to the power of 4 a to the power of 4 b to the power of negative 5 end exponent end fraction end cell equals cell fraction numerator 2 to the power of negative 3 end exponent a cubed b to the power of negative 4 end exponent over denominator open parentheses begin display style 2 to the power of negative 1 end exponent end style close parentheses to the power of 4 a to the power of 4 b to the power of negative 5 end exponent end fraction end cell row blank equals cell fraction numerator 2 to the power of negative 3 end exponent a cubed b to the power of negative 4 end exponent over denominator begin display style 2 to the power of negative 4 end exponent end style a to the power of 4 b to the power of negative 5 end exponent end fraction end cell row blank equals cell 2 to the power of negative 3 minus open parentheses negative 4 close parentheses end exponent a to the power of 3 minus 4 end exponent b to the power of negative 4 minus open parentheses negative 5 close parentheses end exponent end cell row blank equals cell 2 to the power of negative 3 plus 4 end exponent a to the power of negative 1 end exponent b to the power of negative 4 plus 5 end exponent end cell row blank equals cell fraction numerator 2 b over denominator a end fraction end cell end table  

Dengan demikian, nilai dari fraction numerator 2 to the power of negative 3 end exponent a cubed b to the power of negative 4 end exponent over denominator open parentheses begin display style 1 half end style close parentheses to the power of 4 a to the power of 4 b to the power of negative 5 end exponent end fraction  adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 2 b over denominator a end fraction end cell end table.

Jadi, jawaban yang tepat adalah E.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Athaya Dhia Khalila

Pembahasan lengkap banget

Iklan

Iklan

Pertanyaan serupa

Sederhanakan dan hitunglah. a. ( x 5 ​ ) − 2 ⋅ ( 3 x 25 ​ ) 7 ÷ ( 2 x 5 ​ ) − 4

1

4.6

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia