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Pertanyaan

x → 0 lim ​ x 2 − 4 − x ​ ​ = ....

 

  1. begin mathsize 14px style 0 end style 

  2. begin mathsize 14px style 1 end style 

  3. begin mathsize 14px style 2 end style 

  4. begin mathsize 14px style 1 half end style 

  5. begin mathsize 14px style 1 fourth end style 

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Jadi, jawaban yang tepat adalah E.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow 0 of fraction numerator 2 minus square root of 4 minus straight x end root over denominator straight x end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of fraction numerator 2 minus square root of 4 minus straight x end root over denominator straight x end fraction times fraction numerator 2 plus square root of 4 minus straight x end root over denominator 2 plus square root of 4 minus straight x end root end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of fraction numerator 4 minus open parentheses 4 minus straight x close parentheses over denominator straight x open parentheses 2 plus square root of 4 minus straight x end root close parentheses end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of fraction numerator straight x over denominator straight x left parenthesis 2 plus square root of 4 minus straight x end root right parenthesis end fraction end cell row blank equals cell limit as straight x rightwards arrow 0 of fraction numerator 1 over denominator left parenthesis 2 plus square root of 4 minus straight x end root right parenthesis end fraction end cell row blank equals cell fraction numerator 1 over denominator 2 plus square root of 4 end fraction end cell row blank equals cell 1 fourth end cell end table end style 

Jadi, jawaban yang tepat adalah E.

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