Pertanyaan

P ers amaan k u a d r a t x 2 − 2 x + 3 = 0 m e m p u n y ai aka r − aka r x 1 d an x 2 . P ers amaan k u a d r a t y an g aka r − aka r n y a ( x 1 − 4 ) d an ( x 2 − 4 ) a d a l ah ....

$P ers amaan k u a d r a t x^{2} - 2 x + 3 = 0 m e m p u n y ai aka r - aka r x_{1} d an x_{2} . P ers amaan k u a d r a t y an g aka r - aka r n y a (x_{1} - 4) d an (x_{2} - 4) a d a l ah ....$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$A k a r minus a k a r space p e r s a m a a n space k u a d r a t space stack 1 with underbrace below with a below x squared stack stack negative 2 with underbrace below with b below x plus stack 3 with underbrace below with c below equals 0 space a d a l a h space x subscript 1 space d a n space x subscript 2 space D a r i space p e r s a m a a n space d i space a t a s space d i p e r o l e h space colon x subscript 1 plus x subscript 2 equals negative b over a equals negative fraction numerator open parentheses negative 2 close parentheses over denominator 1 end fraction equals 2 x subscript 1. x subscript 2 equals c over a equals 3 over 1 equals 3 R u m u s space m e m b u a t space p e r s a m a a n space k u a d r a t space b a r u space y a n g space a k a r minus a k a r n y a space p space d a n space q space a d a l a h space colon x squared minus stack stack open parentheses p plus q close parentheses with underbrace below x with penjumlahan straight space akar minus akarnya below plus stack stack p. q with underbrace below with perkalian straight space akar minus akarnya below equals 0 S e h i n g g a space colon space • H a s i l space p e n j u m l a h a n n y a space a d a l a h space open parentheses x subscript 1 minus 4 close parentheses plus open parentheses x subscript 2 minus 4 close parentheses equals x subscript 1 plus x subscript 2 minus 4 minus 4 equals 2 minus 8 equals negative 6 • H a s i l space p e r k a l i a n n y a space a d a l a h space space open parentheses x subscript 1 minus 4 close parentheses open parentheses x subscript 2 minus 4 close parentheses equals x subscript 1 x subscript 2 minus 4 x subscript 1 minus 4 x subscript 2 plus 16 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals x subscript 1 x subscript 2 minus 4 open parentheses x subscript 1 plus x subscript 2 close parentheses plus 16 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3 minus 4 open parentheses 2 close parentheses plus 16 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 11 J a d i space p e r s a m a a n space k u a d r a t space b a r u n y a space a d a l a h space space x squared minus open parentheses negative 6 close parentheses x plus 11 equals 0 ⟺ x squared plus 6 x plus 11 equals 0$

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3.6 (3 rating)

Manu Manu

Banyak bct

Pertanyaan serupa

[UN 2010] Jika p dan q adalah akar-akar persamaan x 2 − 5 x − 1 = 0 ,maka persamaan kuadrat baru yang akar-akarnya 2p+1 dan 2q+1 adalah …

4.1

Jawaban terverifikasi

Persamaan kuadrat baru yang akar-akarnya dua lebihnya dari akar-akar persamaan 2 x 2 + 4 x + 3 = 0 adalah...

4.0

Jawaban terverifikasi

[UN 2012] Diketahui persamaan kuadrat x 2 − 10 x + 24 = 0 mempunyai akar-akar x 1 dan x 2 dengan x 1 > x 2 . Nilai dari 10 x 1 + 5 x 2 adalah...

4.0

Jawaban terverifikasi

Jika akar-akar persamaan kuadrat ,maka persamaan kuadrat yang akar-akarnya x 1 + x 1 1 d an x 2 + x 2 1 adalah...

5.0

Jawaban terverifikasi

Jika akar-akar x 2 − a x − b = 0 saling berkebalikan dan salah satu akarnya merupakan bilangan bulat positif, maka nilai terkecil yang mungkin untuk a - badalah ...

0.0

Jawaban terverifikasi