Pertanyaan

100 mL NaOH 1,8 M + 100 mL CH 3 COOH 1,8 M ke dalam larutan garam uji yang terbentuk ditetesi larutan Ni(NO 3 ) 2 sampai keadaan tepat jenuh Ni(OH) 2 . Kalau K w = 10 -14 ; K a = 10 -5 ; K sp Ni(OH) 2 = 1,8 x 10 -14 maka [Ni 2+ ] pada saat tepat jenuh (tepat saat terjadi pengendapan) adalah ….

100 mL NaOH 1,8 M + 100 mL CH₃COOH 1,8 M ke dalam larutan garam uji yang terbentuk ditetesi larutan Ni(NO₃)₂ sampai keadaan tepat jenuh Ni(OH)₂ .
Kalau K_w = 10^-14 ; K_a = 10^-5 ; K_sp Ni(OH)₂ = 1,8 x 10^-14 maka [Ni²⁺] pada saat tepat jenuh (tepat saat terjadi pengendapan) adalah ….

2 x 10^-2 M
2 x 10^-3 M
2 x 10^-4 M
2 x 10^-5 M
2 x 10^-6 M

N. Puji

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Pembahasan

$begin mathsize 14px style Perlu space dihitung space terlebih space dulu space jumlah space mol space HCl space dan space NH subscript 3 space dengan space menggunakan space rumus space gas space ideal Mol space CH subscript 3 COOH space equals space straight M space straight x space straight V space equals space 1 comma 8 straight M space straight x space 100 space mL space equals space 180 space mmol space Mol space NaOH space equals space straight M space straight x space straight V space equals space 1 comma 8 straight M space straight x space 100 space mL space equals space 180 space mmol space Persamaan space reaksi space colon space space space space space space space space space space space space space space space space space space space space space space space space space space CH subscript 3 COOH left parenthesis aq right parenthesis space plus space NaOH left parenthesis aq right parenthesis space space space rightwards arrow space CH subscript 3 COONa left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space Mula minus mula space colon space space space space space space space space space space 180 space mmol space space space space space space space space space space 180 space mmol space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space minus space Reaksi space colon space space space space space space space space space space space space minus space 180 space mmol space space space space space space space space minus space 180 space mmol space space space space space space space space space space plus space 180 space mmol space space space space space plus space space 180 space mmol top enclose Sisa space colon space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space 180 space mmol space space space space space space space space space space space space space 180 space mmol end enclose Karena space yang space tersisa space hanya space garam space dan space air comma space maka space menggunakan space rumus space hidrolisis. space space space left square bracket straight G right square bracket space equals space space equals space space equals space 9.10 to the power of negative 1 end exponent space straight M space space OH minus space equals space space space equals space space space space equals space space space space equals space 3. to the power of 10 minus 5 end exponent space space Ni left parenthesis OH right parenthesis subscript 2 space space Ni squared plus space plus space 2 OH to the power of minus space Karena space larutan space tersebut space tepat space jenuh comma space maka space space Ksp space equals space Qsp space space 1 comma 8 space cross times space 10 to the power of negative 14 end exponent space equals space left square bracket Ni squared plus right square bracket space left square bracket OH minus right square bracket to the power of 2 space end exponent 1 comma 8 space cross times space 10 to the power of negative 14 end exponent space equals space left square bracket Ni squared plus right square bracket space left square bracket 3 space cross times space 10 to the power of negative 5 end exponent right square bracket squared space left square bracket Ni to the power of 2 plus end exponent right square bracket space equals space space fraction numerator 1 comma 8 space cross times space 10 to the power of negative 14 end exponent space over denominator 9 space cross times space 10 to the power of negative 10 end exponent end fraction equals space 2 space cross times space 10 to the power of negative 5 end exponent space straight M end style$

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