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Dalam satu liter larutan terdapatgaram Kalsium Klorida memiliki konsentrasi 0,01 M. Jika ditambahkan 67 mg garam Natrium Oksalat sebanyak 250 mL. ( Mr Natrium Oksalat = 134 ; Ksp Kalsium Oksalat = 2 , 3 x 1 0 − 9 ). Apakah terbentuk endapan ?

Dalam satu liter larutan terdapat garam Kalsium Klorida memiliki konsentrasi 0,01 M. Jika ditambahkan 67 mg garam Natrium Oksalat sebanyak 250 mL.

( ; ).

Apakah terbentuk endapan ?

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G. Suprobo

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

Oleh karena nilai , maka kalsium oksalat akan mengendap.

table attributes columnalign right center left columnspacing 0px end attributes row cell mol space Natrium space oksalat end cell equals cell fraction numerator 67 x 10 to the power of negative sign 3 end exponent space mol over denominator 134 space g forward slash mol end fraction end cell row blank equals cell 5 x 10 to the power of negative sign 4 end exponent space mol end cell row cell Molaritas space Natrium space oksalat end cell equals cell fraction numerator 5 x 10 to the power of negative sign 4 end exponent space mol over denominator 0 comma 25 space L end fraction end cell row blank equals cell 2 x 10 to the power of negative sign 3 end exponent M end cell row cell Molaritas space kalsium space klorida end cell equals cell 0 comma 01 space M end cell end table

Ca Cl subscript 2 space space yields Ca to the power of 2 plus sign space space space plus space space 2 Cl to the power of minus sign 0 comma 01 space M space space space space 0 comma 01 space M space space space 0 comma 01 space M  maka space left square bracket Ca to the power of 2 plus sign space right square bracket equals 0 comma 01 space M   Na subscript 2 C subscript 2 O subscript 4 yields 2 Na to the power of plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign 0 comma 002 space M space space space 0 comma 002 space M space space 0 comma 002 space M space space space space space  maka space open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets equals space 0 comma 002 space M space

 

table attributes columnalign right center left columnspacing 0px end attributes row cell Qc space Ca C subscript 2 O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets end cell row blank equals cell left parenthesis 0 comma 01 right parenthesis left parenthesis 0 comma 002 right parenthesis end cell row blank equals cell open parentheses 1 x 10 to the power of negative sign 2 end exponent close parentheses left parenthesis 2 x 10 to the power of negative sign 3 end exponent right parenthesis end cell row blank equals cell 2 x 10 to the power of negative sign 5 end exponent end cell row blank blank blank row blank blank blank end table

Oleh karena nilai Qc greater than Kc, maka kalsium oksalat akan mengendap.

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