Roboguru

Pertanyaan

begin mathsize 14px style limit as straight x rightwards arrow infinity of space straight x space cot space open parentheses 1 over straight x close parentheses space sin space open parentheses 1 over straight x squared close parentheses equals end style.....

  1. -2

  2. -1

  3. 0

  4. 1

  5. 2

A. Rizky

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style limit as straight x rightwards arrow straight infinity of invisible function application space straight x space cot space invisible function application open parentheses 1 over straight x close parentheses space sin space invisible function application open parentheses 1 over straight x squared close parentheses  Misalkan  straight u equals 1 over straight x space maka space straight x equals 1 over straight u space dan space 1 over straight x squared equals straight u squared  Untuk space straight x rightwards arrow infinity space maka space straight u rightwards arrow 0    limit as straight u rightwards arrow 0 of invisible function application space 1 over straight u space cot space invisible function application straight u. space sin space invisible function application straight u squared  limit as straight u rightwards arrow 0 of space invisible function application fraction numerator sin space invisible function application straight u squared over denominator straight u. tan space invisible function application straight u end fraction equals 1  end style

70

5.0 (3 rating)

Pertanyaan serupa

Tentukan nilai x→∞lim​3x+2sinx−8cos4x−6x​!

19

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia