x→5lim​ (x2−4x+4)2=. . .

Pertanyaan

limit as x rightwards arrow 5 of space left parenthesis x squared minus 4 x plus 4 right parenthesis squared equals. . .

  1. negative 343 

  2. negative 27 

  3. 27

  4. 81 

  5. 343

D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

Pembahasan

Jawaban yang benar untuk pertanyaan tersebut adalah D.

Ingat sifat limit 

  • limit as x rightwards arrow a of space x equals a
  • limit as x rightwards arrow a of space k equals k
  • limit as x rightwards arrow a of space k x equals k times limit as x rightwards arrow a of space x equals k times a
  • limit as x rightwards arrow a of space open square brackets f left parenthesis x right parenthesis minus g left parenthesis x right parenthesis close square brackets equals limit as x rightwards arrow a of f left parenthesis x right parenthesis minus limit as x rightwards arrow a of g left parenthesis x right parenthesis
  • limit as x rightwards arrow a of space open square brackets f left parenthesis x right parenthesis plus g left parenthesis x right parenthesis close square brackets equals limit as x rightwards arrow a of f left parenthesis x right parenthesis plus g left parenthesis x right parenthesis
  • limit as x rightwards arrow a of space open square brackets f left parenthesis x right parenthesis. g left parenthesis x right parenthesis close square brackets equals limit as x rightwards arrow a of f left parenthesis x right parenthesis. limit as x rightwards arrow a of g left parenthesis x right parenthesis
  • limit as x rightwards arrow a of space open square brackets f left parenthesis x right parenthesis close square brackets to the power of n equals open square brackets limit as x rightwards arrow a of f left parenthesis x right parenthesis close square brackets to the power of n

Dengan menggunakan sifat-sifat di atas maka diperoleh perhitungan sebagai berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 5 of space left parenthesis x squared minus 4 x plus 4 right parenthesis squared end cell equals cell open parentheses limit as x rightwards arrow 5 of space left parenthesis x squared minus 4 x plus 4 right parenthesis close parentheses squared end cell row blank equals cell open parentheses limit as x rightwards arrow 5 of x squared minus limit as x rightwards arrow 5 of 4 x plus limit as x rightwards arrow 5 of 4 close parentheses squared end cell row blank equals cell open parentheses open parentheses limit as x rightwards arrow 5 of x times limit as x rightwards arrow 5 of x close parentheses minus open parentheses 4 times limit as x rightwards arrow 5 of x close parentheses plus limit as x rightwards arrow 5 of 4 close parentheses squared end cell row blank equals cell open parentheses open parentheses 5 times 5 close parentheses minus open parentheses 4 times 5 close parentheses plus 4 close parentheses squared end cell row blank equals cell open parentheses 25 minus 20 plus 4 close parentheses squared end cell row blank equals cell 9 squared end cell row blank equals 81 end table

Oleh karena itu, jawaban yang benar adalah D.

97

5.0 (7 rating)

Pertanyaan serupa

Diberikan x→alim​f(x)=3 dan x→alim​g(x)=−1.  Hitunglah nilai setiap limit berikut. a. x→alim​f2(x)+g2(x)​  b. x→alim​f(x)+g(x)2f(x)−3g(x)​  c. x→alim​3g(x)​[f(x)+3]  d. x→alim​[f(x)−3]4

83

4.8

Jawaban terverifikasi

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