Iklan

Iklan

Pertanyaan

x → 2 lim ​ x 2 + 5 x + 6 x 2 − 10 x − 24 ​ = ....

 = ....

Iklan

R. Novianto

Master Teacher

Mahasiswa/Alumni Universitas Tanjungpura Pontianak

Jawaban terverifikasi

Jawaban

  begin mathsize 14px style limit as straight x rightwards arrow 2 of fraction numerator straight x squared minus 10 straight x minus 24 over denominator straight x squared plus 5 straight x plus 6 end fraction equals negative 2 over 3 end style  

Iklan

Pembahasan

soal di atas merupakan limit tak tentu fungsi aljabar yang penyelesaiannya menggunakan dalil L'hospital, yaitu dengan menggunakan turunan. Perhatikan perhitungan berikut ! Jadi,

soal di atas merupakan limit tak tentu fungsi aljabar yang penyelesaiannya menggunakan dalil L'hospital, yaitu dengan menggunakan turunan.

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell limit as straight x rightwards arrow straight a of fraction numerator straight f open parentheses straight x close parentheses over denominator straight g open parentheses straight x close parentheses end fraction end cell cell equals limit as straight x rightwards arrow straight a of end cell cell fraction numerator straight f apostrophe open parentheses straight x close parentheses over denominator straight g apostrophe open parentheses straight x close parentheses end fraction end cell end table end style 

Perhatikan perhitungan berikut !
 

 begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell limit as straight x rightwards arrow 2 of fraction numerator straight x squared minus 10 straight x minus 24 over denominator straight x squared plus 5 straight x plus 6 end fraction end cell equals cell limit as straight x rightwards arrow 2 of fraction numerator 2 straight x minus 10 over denominator 2 straight x plus 5 end fraction end cell row blank equals cell fraction numerator 2 open parentheses 2 close parentheses minus 10 over denominator 2 open parentheses 2 close parentheses plus 5 end fraction end cell row blank equals cell fraction numerator 4 minus 10 over denominator 4 plus 5 end fraction end cell row blank equals cell fraction numerator negative 6 over denominator 9 end fraction end cell row blank equals cell negative 6 over 9 end cell row blank equals cell negative 2 over 3 end cell end table end style  
 

Jadi,  begin mathsize 14px style limit as straight x rightwards arrow 2 of fraction numerator straight x squared minus 10 straight x minus 24 over denominator straight x squared plus 5 straight x plus 6 end fraction equals negative 2 over 3 end style  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

6

Salsabila Kumala

Bantu banget

Cut Zidda Ulya

Makasih ❤️

Hasna Amalia

Bantu banget

Iklan

Iklan

Pertanyaan serupa

Selidiki fungsi tersebut mempunyai limit atau tidak x → 1 lim ​ x 2 − 1 x 4 − 1 ​ ,berikan alasan!

10

4.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia