KK
Kevz K
29 September 2025 15:29
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KK
Kevz K
29 September 2025 15:29
Pertanyaan
Tolong kerjakan rek makasih sebelumnya😹🙏
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FI
Fadhil I
29 September 2025 16:32
<p>u1 = x^(1/3)</p><p>u2 = x^(1/2)</p><p> </p><p>r = u2/u1 </p><p>= x^(1/2) / x^(1/3) </p><p>= x^(1/2-1/3) </p><p>= x^(1/6)</p><p> </p><p>u5 = u1×r⁴</p><p>= x^(1/3) × {x^(1/6}^4</p><p>= x^(1/3) × x^(1/6×4)</p><p>= x^(1/3) × x^(2/3)</p><p>= x^(1/3 + 2/3)</p><p>= x^(3/3)</p><p>= x ^(1)</p><p>= x</p><p> </p><p>Jawabannya A</p><p> </p><p> </p>
u1 = x^(1/3)
u2 = x^(1/2)
r = u2/u1
= x^(1/2) / x^(1/3)
= x^(1/2-1/3)
= x^(1/6)
u5 = u1×r⁴
= x^(1/3) × {x^(1/6}^4
= x^(1/3) × x^(1/6×4)
= x^(1/3) × x^(2/3)
= x^(1/3 + 2/3)
= x^(3/3)
= x ^(1)
= x
Jawabannya A
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