Shafiyyah A

14 Desember 2024 03:52

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Shafiyyah A

14 Desember 2024 03:52

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Atiqotun N

14 Desember 2024 08:49

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<p>Buku= x</p><p>Pensil= y</p><p>Penghapus =z</p><p>4x +3y= 41.000 pers....1</p><p>2y+3z= 44.000 pers....2</p><p>X+2z= 25.000 pers.....3</p><p>Jawab:&nbsp;</p><p>1. Eliminasikan persamaan 2 dan persamaan 3</p><p>&nbsp; &nbsp; &nbsp; 2y+3z= 44.000 ×2</p><p>&nbsp; &nbsp; &nbsp;&nbsp;<u>X+2z= 25.000 &nbsp; ×3 &nbsp; &nbsp; &nbsp; &nbsp;</u></p><p>&nbsp; &nbsp; &nbsp; 4y+6z= 88.000</p><p>&nbsp; &nbsp; &nbsp;&nbsp;<u>3x+6z=75.000 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; -</u></p><p>&nbsp; &nbsp; &nbsp; 4y-3x=13.000 pers.....4</p><p>&nbsp;2. Eliminasikan persamaan 4 dan persamaan 1</p><p>&nbsp; &nbsp; &nbsp; &nbsp;4y-3x=13.000 x4</p><p>&nbsp; &nbsp; &nbsp; &nbsp;<u>3y+4x=41.000 x3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</u></p><p>&nbsp; &nbsp; &nbsp; &nbsp; 16y-12x=52.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<u> 9y+12x=123.000 &nbsp; &nbsp; &nbsp;+</u></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 25y=175.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;y= <u>175.000</u></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;25</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; y= 7.000</p><p>3. Substitusikan y= 7.000 ke pers...1</p><p>&nbsp; &nbsp; &nbsp; 4x +3y= 41.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp;4x+3(7.000)=41.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 4x+21.000=41.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 4x=41.000-21.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; X= <u>20.000</u></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;4</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; X=5.000</p><p>4. Substitusikan X=5.000 ke pers...3</p><p>&nbsp; &nbsp; &nbsp; X+2z= 25.000</p><p>&nbsp; &nbsp; &nbsp; 5.000+2z= 25.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2z=25.000-5.000</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Z= <u>20.000</u></p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Z= 10.000</p><p>Jadi, harga 1 buku, 1 pensil, dan 1 penghapus adalah 7.000, 5.000, dan 10.000</p><p>&nbsp;</p>

Buku= x

Pensil= y

Penghapus =z

4x +3y= 41.000 pers....1

2y+3z= 44.000 pers....2

X+2z= 25.000 pers.....3

Jawab: 

1. Eliminasikan persamaan 2 dan persamaan 3

      2y+3z= 44.000 ×2

      X+2z= 25.000   ×3        

      4y+6z= 88.000

      3x+6z=75.000               -

      4y-3x=13.000 pers.....4

 2. Eliminasikan persamaan 4 dan persamaan 1

       4y-3x=13.000 x4

       3y+4x=41.000 x3          

        16y-12x=52.000

         9y+12x=123.000      +

              25y=175.000

                   y= 175.000

                           25

                    y= 7.000

3. Substitusikan y= 7.000 ke pers...1

      4x +3y= 41.000

       4x+3(7.000)=41.000

        4x+21.000=41.000

                  4x=41.000-21.000

                    X= 20.000

                               4

                    X=5.000

4. Substitusikan X=5.000 ke pers...3

      X+2z= 25.000

      5.000+2z= 25.000

                2z=25.000-5.000

                  Z= 20.000

                            2

                  Z= 10.000

Jadi, harga 1 buku, 1 pensil, dan 1 penghapus adalah 7.000, 5.000, dan 10.000

 


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Jap S

Dijawab 6 hari yang lalu

Jawaban terverifikasi

<p>4b + 3p = 41000...(1)</p><p>2p + 3h = 44000...(2)</p><p>1b + 2h = 25000...(3)</p><p>Dieliminasikan pers 2&amp;3, pers 2 dikali 2, pers 3 dikali 3</p><p>&nbsp;</p><p>4p + 6h = 88000</p><p>3b + 6h = 75000</p><p>--------------------------- -</p><p>4p - 3b = 13000....(4)</p><p>Pers 1 &amp; 4 dieliminasi (pers 1 dikali 3, pers 4 dikali 4)</p><p>9p + 12b = 123000</p><p>16p - 12b = 52000</p><p>------------------------------ +</p><p>25p = 175000</p><p>p= 7000 disubs ke pers 1</p><p>&nbsp;</p><p>4b + 3p = 41000</p><p>4b + 3(7000) = 41000</p><p>4b + 21000 = 41000</p><p>4b = 41000-21000 = 20000</p><p>b = 20000/4</p><p>b = 5000 disubs ke pers 3</p><p>&nbsp;</p><p>b + 2h = 25000</p><p>5000 + 2h = 25000</p><p>2h = 25000-5000 = 20000</p><p>h = 20000/2</p><p>h = 10000</p><p>&nbsp;</p><p>Ditanyakan b+p+h= 5000+7000+10000 = 22000</p>

4b + 3p = 41000...(1)

2p + 3h = 44000...(2)

1b + 2h = 25000...(3)

Dieliminasikan pers 2&3, pers 2 dikali 2, pers 3 dikali 3

 

4p + 6h = 88000

3b + 6h = 75000

--------------------------- -

4p - 3b = 13000....(4)

Pers 1 & 4 dieliminasi (pers 1 dikali 3, pers 4 dikali 4)

9p + 12b = 123000

16p - 12b = 52000

------------------------------ +

25p = 175000

p= 7000 disubs ke pers 1

 

4b + 3p = 41000

4b + 3(7000) = 41000

4b + 21000 = 41000

4b = 41000-21000 = 20000

b = 20000/4

b = 5000 disubs ke pers 3

 

b + 2h = 25000

5000 + 2h = 25000

2h = 25000-5000 = 20000

h = 20000/2

h = 10000

 

Ditanyakan b+p+h= 5000+7000+10000 = 22000


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