tolong, guys. urgent :(

<p>2x + y + 4z = 14...(1)</p><p>x - y + 3z = 6...(2)</p><p>x + 4y + z = 12...(3)</p><p>&nbsp;</p><p>Eliminasi (1) dan (2) untuk menghilangkan variabel x :</p><p>&nbsp;</p><p>2x + y + 4z = 14...(1)</p><p>&nbsp; x - y + 3z = 6...(2) (<i>dikali 2</i>)</p><p>--------------------- -</p><p>3y - 2z = 2...(4)</p><p>&nbsp;</p><p>Eliminasi (2) dan (3) :</p><p>x - y + 3z = 6...(2)</p><p>x + 4y + z = 12...(3)</p><p>----------------------- -</p><p>-5y + 2z = -6...(5)</p><p>&nbsp;</p><p>Eliminasi (4) dan (5) untuk menghilangkan variabel z :</p><p>3y - 2z = 2</p><p>-5y + 2z = -6</p><p>-------------------- +</p><p>-2y = -4</p><p>y = (-4)/(-2)&nbsp;</p><p>y = 2.</p><p>&nbsp;</p><p>Subtitusikan y baik ke dalam (4) ataupun (5) :</p><p>3y - 2z = 2</p><p>3(2) - 2z = 2</p><p>6 - 2z = 2</p><p>-2z = 2 - 6</p><p>-2z = -4</p><p>z = (-4)/(-2)</p><p>z = 2.</p><p>&nbsp;</p><p>Subtitusikan y dan z baik ke dalam (1), (2), ataupun (3) :</p><p>x - y + 3z = 6</p><p>x - (2) + 3(2) = 6</p><p>x - 2 + 6 = 6</p><p>x + 4 = 6</p><p>x = 6 - 4</p><p>x = 2.</p><p>&nbsp;</p><p>Jadi, HP = {2, 2, 2}. (<i>{x, y, z}</i>)</p><p>&nbsp;</p><p>Semoga membantu.</p>