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Cholis I
19 September 2025 05:40
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CI
Cholis I
19 September 2025 05:40
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tolong di jawabππ»ππ»ππ»ππ»
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000000000000000000000000c025a2e1de5c7ab31c3c48313f9f7e14572461 0
19 September 2025 06:15
<p>f(x) = 1/β(6x + 3)</p><p>f(x) = (6x + 3)<sup>-1/2</sup></p><p> </p><p>f'(x)</p><p>= -1/2 (6x + 3)<sup>-1/2 - 1</sup> Γ 6</p><p>= -3/((6x + 3)<sup>-1/2</sup>(6x + 3)<sup>-1</sup>)</p><p>= <strong>-3 / (6x + 3)β(6x + 3)</strong></p>
f(x) = 1/β(6x + 3)
f(x) = (6x + 3)-1/2
f'(x)
= -1/2 (6x + 3)-1/2 - 1 Γ 6
= -3/((6x + 3)-1/2(6x + 3)-1)
= -3 / (6x + 3)β(6x + 3)
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