tolong bantu

<p>1a.&nbsp;</p><p>f(x) = x⁷ − 3x⁵ + 2x² − 8<br>f'(x) = 7x⁶ − 15x⁴ + 4x</p><p><br>1b.&nbsp;</p><p>f(x) = (5/6)x⁶ + (2/3)x³ − (1/2)x² + 8x − 5<br>f'(x) = 5x⁵ + 2x² − x + 8</p><p><br>2a.&nbsp;</p><p>f(x) = (x² − 4)(x² + 2x − 1)<br>pakai aturan perkalian: f'(x) = 2x(x²+2x−1) + (x²−4)(2x+2)<br>f'(x) = 4x³ + 6x² − 10x − 8</p><p><br>2b.&nbsp;</p><p>lf(x) = (3x − 2)⁵(x² − 3x + 2)³<br>pakai aturan perkalian + rantai:<br>u = (3x−2)⁵ → u' = 15(3x−2)⁴<br>v = (x²−3x+2)³ → v' = 3(2x−3)(x²−3x+2)²<br>f'(x) = 15(3x−2)⁴(x²−3x+2)³ + 3(3x−2)⁵(2x−3)(x²−3x+2)²<br>Faktorkan (3x−2)⁴(x²−3x+2)²:<br>f'(x) = 3(3x − 2)⁴(x² − 3x + 2)²(11x² − 28x + 16)</p>