ZA
Zahra A
11 September 2025 05:24
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ZA
Zahra A
11 September 2025 05:24
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MK
Mohamad K
11 September 2025 08:19
<p>root(3)(27)/4^(-1) + (25^(1/2))/(root(2)(8))^2 -> 25^(1/2) = sqrt(25) = 5 , (sqrt(8))^2 = 2^2 = 4 , = 5/4 , root(3)(27) = 3 , 4^(-1) = 1/4 , = 3/(1/4) = 3 xx 4 = 12 , => 12 + 5/4 = 48/4 + 5/4 = (48+5)/4 = 53/4 :. hasil dari root(3)(27)/4^(-1) + (25^(1/2))/(root(2)(8))^2 = 53/4</p>
root(3)(27)/4^(-1) + (25^(1/2))/(root(2)(8))^2 -> 25^(1/2) = sqrt(25) = 5 , (sqrt(8))^2 = 2^2 = 4 , = 5/4 , root(3)(27) = 3 , 4^(-1) = 1/4 , = 3/(1/4) = 3 xx 4 = 12 , => 12 + 5/4 = 48/4 + 5/4 = (48+5)/4 = 53/4 :. hasil dari root(3)(27)/4^(-1) + (25^(1/2))/(root(2)(8))^2 = 53/4
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