Mohon bantuannya kakak² ini jawaban yg benarnya apaya??

<p>Baik terima kasih atas pertanyaannya</p><p>Berikut adalah solusi dari pertanyaan-pertanyaan tersebut :</p><ul><li><strong>PERTANYAAN 1</strong></li></ul><p>(x^{-5}y^{1/3})^{-3/5} = x^{a}y^{b}</p><p>x^{3}y^{-1/5} = x^{a}y^{b}</p><p>a = 3, b = -1/5</p><p>&nbsp;</p><p>a+b = 3 - 1/5 = <strong><u>14/5&nbsp;</u></strong></p><p>&nbsp;</p><ul><li><strong>PERTANYAAN 2</strong></li></ul><p>4x^2 - 8x + 3 = 0</p><p>(4x - 6)(x - 1/2) = 0</p><p>x = 3/2 atau 1/2</p><p>&nbsp;</p><p>x_{2} ≥ x_{1}</p><p>x_{2} = 3/2</p><p>x_{1} = 1/2</p><p>&nbsp;</p><p>x_{2}^{2} - x_{1}^{2}</p><p>(3^2)^2 - (1/2)^2</p><p>(3/2 + 1/2)(3/2 - 1/2) = <strong><u>2</u></strong></p><p>&nbsp;</p><ul><li><strong>PERTANYAAN 3</strong></li></ul><p>(x^{4}y^{2}z^{2})^{1/4} = x^{a}y^{b}z^{c}</p><p>xy^{1/2}z^{1/2} = x^{a}y^{b}z^{c}</p><p>a = 1</p><p>b = 1/2</p><p>c = 1/2</p><p>&nbsp;</p><p>a+b+c = 1 + 1/2 + 1/2 = <strong><u>2</u></strong></p><p>&nbsp;</p><ul><li><strong>PERTANYAAN 4</strong></li></ul><p>Cos (2x) ≠ 1 - cos^{2}(x)</p><p>cos(2x) = cos^{2}x - sin^{2}x</p><p>= cos^{2}x - (1 - cos^{2}x) [Sebab cos^{2}x + sin^{2}x = 1 ⇒ sin^{2}x = 1 - cos^{2}x]</p><p>= cos^{2}x - 1 + cos^{2}x</p><p>= 2cos^{2}x - 1</p><p>Sehingga jawabannya adalah <strong><u>C</u></strong></p><p>&nbsp;</p><p>Semoga membantu 😄👍</p>