Mitania V
28 September 2025 16:56
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Mitania V
28 September 2025 16:56
Pertanyaan
haloo ada yang bisa bantuu🫠🫠

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Fadhil I
28 September 2025 20:53
Ingat bentuk
• ²log 5 = 1/⁵log 2
• ³log 34 × ³⁴log 5 = ³log 5
• ⁵log(a×b×c) = ⁵log a + ⁵log b + ⁵log c
• ³⁷log 37 = 1
• ⁵log 13⁴ = 4 ⁵log 13
²log 3 = a
¹/³log 2 = a
³log 2 = 1/a
³log 7 = b
¹/⁷log 3 = b
⁷log 3= 1/b
²log 3 × ³log 7 = ab
²log 7 = ab
1/(⁷log 2) = ab
⁷log 2 = 1/(ab)
5a) ¹⁴log 56
= ¹⁴log(14×4)
= ¹⁴log 14 + ¹⁴ log 4
= 1 + ¹⁴log 2²
= 1 + 2¹⁴log 2
= 1 + 2/²log 14
= 1 + 2/²log(7×2)
= 1 + 2/(²log 7 + ²log 2)
= 1 + 2/(ab+1)
( Boleh dilanjutin bentuknya jadi berikut dengan mengingat 1 = (ab+1)/(ab+1) )
= (ab+1)/(ab+1) + 2/(ab+1)
= (ab+1+2)/(ab+1)
= (ab+3)/(ab+1)
5b) ⁶log 84
= ⁶log(6×7×2)
= ⁶log 6 + ⁶log 7 + ⁶log 2
= 1 + 1/⁷log 6 + 1/²log 6
= 1 + 1/⁷log(2×3) + 1/²log(2×3)
= 1 + 1/(⁷log 2 + ⁷log 3) + 1/(²log 2 + ²log 3)
= 1 + 1/(1/(ab) + 1/b) + 1/(1 + a)
= 1 + 1/(1/(ab) + a/(ab)) + 1/(1+a)
= 1 + 1/((a+1)/ab) + 1/(1+a)
= 1 + ab/(a+1) + 1/(a+1)
= 1 + (ab+1)/(a+1)
( Boleh dilanjutin jadi bentuk berikut dgn mengingat 1 = (a+1)/(a+1) )
= (a+1)/(a+1) + (ab+1)/(a+1)
= (a+1+ab+1)/(a+1)
= (ab+a+2)/(a+1)
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Mitania V
28 September 2025 22:24
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