Griselda G
08 September 2026 07:23
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Griselda G
08 September 2026 07:23
Pertanyaan
Guys please help, soal ini rather confusing buat aku, trims ;)
Guys please help, soal ini rather confusing buat aku, trims ;)
25
2
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Nazmi N
08 September 2026 11:12
<p> </p><p>ini jawaban nya</p><p> </p>
ini jawaban nya
· 4.0 (2)
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Muhammad F
17 September 2026 01:53
<p>1. (8^(1/2) × 32^(1/2)) / 16^(1/4)</p><p>= ((2^3)^(1/2) × (2^5)^(1/2)) / (2^4)^(1/4)</p><p>= (2^(3/2) × 2^(5/2)) / 2^1</p><p>= 2^(3/2 + 5/2) / 2^1</p><p>= 2^(8/2) / 2^1</p><p>= 2^4 / 2^1</p><p>= 2^(4 - 1)</p><p>= 2^3</p><p>= 8</p><p> </p><p>2. 3x^(-3) y^2 × (x^2 y)^(-4)</p><p>= 3x^(-3) y^2 × x^(-8) y^(-4)</p><p>= 3 × x^(-3 + (-8)) × y^(2 + (-4))</p><p>= 3x^(-11) y^(-2)</p><p>= 3 / (x^11 y^2)</p>
1. (8^(1/2) × 32^(1/2)) / 16^(1/4)
= ((2^3)^(1/2) × (2^5)^(1/2)) / (2^4)^(1/4)
= (2^(3/2) × 2^(5/2)) / 2^1
= 2^(3/2 + 5/2) / 2^1
= 2^(8/2) / 2^1
= 2^4 / 2^1
= 2^(4 - 1)
= 2^3
= 8
2. 3x^(-3) y^2 × (x^2 y)^(-4)
= 3x^(-3) y^2 × x^(-8) y^(-4)
= 3 × x^(-3 + (-8)) × y^(2 + (-4))
= 3x^(-11) y^(-2)
= 3 / (x^11 y^2)
· 5.0 (1)
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