Grafik fk f(x) = -2x²-5x+12 memotong sumbu x di titik

<p>dengan cara memfaktorkan persamaan :&nbsp;</p><p>-2x² - 8x + 3x + 12 = 0</p><p>-2x(x + 4) + 3(x + 4) = 0</p><p>(-2x + 3)(x + 4) = 0</p><p>&nbsp;</p><p>Untuk menyelesaikan persamaan (-2x + 3)(x + 4) = 0, kita menyamakan masing-masing faktor dengan nol:</p><ul><li>-2x + 3 = 0 =&gt; -2x = -3 =&gt; x = 3/2</li><li>x+4=0 =&gt; x=-4 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Menentukan titik potong : Jadi, x = 3/2 dan x = -4 adalah koordinat x dari titik potong grafik fungsi dengan sumbu x &nbsp; . Titik potongnya adalah (3/2, 0) dan (-4, 0).</li></ul>