diketahui sebuah timbel tersebut tabung dan 2 kerucut yang menyatu. hitunglah luas dan volume timbul tersebut jika jari" kerucut sama tinggi kerucut dan tinggi tabung sama jari" adalah 7m tingginya 7cm

<p>Jawabannya yaitu luas timbel : 616√2 + 616 cm² dan volume timbel : 1.796,67 cm³</p><p>&nbsp;</p><p>Pembahasan :</p><p>a. Luas timbel</p><p>Rumus selimut tabung = 2 × π × r × t</p><p>Rumus selimut kerucut = π × r × s</p><p>s = √7² + 7²</p><p>&nbsp; = √49 + 49</p><p>&nbsp; = 7√2</p><p>L timbel = 2 × luas selimut kerucut + luas selimut tabung&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2 × π × r × s + 2 × π × r × t</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2 × 22/7 × 7 × 7 √2 + 2 × 22/7 × 7 × 7</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 88 × 7√2 + 88 × 7</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 616√2 + 616 cm²</p><p>b. Volume timbel</p><p>V tabung = π × r² × t</p><p>V kerucut = ⅓ × π × r² × t</p><p>V timbel = v tabung + 2× v kerucut</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = π × r² × t + 2 × ( ⅓ × π × r² × t)</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 22/7 × 7² × 7 + ⅔ × 22/7 × 7² × 7</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 22 × 49 + ⅔ × 22 × 49</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1.078 + 2.156/3</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = &nbsp;1.078 + &nbsp; &nbsp;718,67</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 1.796,67 cm³</p><p>&nbsp;</p><p>&nbsp;</p>