Diketahui panjang PA = 15 cm, AB = 24 cm, dan besar APB=108°. Luas tembereng adalah.... bisa bantu jawab ga kak😔

<p>Jawaban &nbsp;<strong>B. 103,95 cm²</strong></p><p>&nbsp;</p><p><strong>Pembahasan&nbsp;</strong></p><p>PA = PB karena merupakan jari jari lingkaran yaitu 15 cm.&nbsp;</p><p>&nbsp;</p><p>APB merupakan luas juring lingkaran (sektor lingkaran dengan sudut pusat APB 108°</p><p>Luas juring APB = (∠APB / 360) × πr²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = (108/360) × 3,14 × 15²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 211,95 cm²</p><p>&nbsp;</p><p>Perhatikan ΔAPB.&nbsp;</p><p>Dari titik pusat lingkaran P, dibuat garis tegak lurus (apotema) terhadap garis AB sehingga titik potongnya (semisal titik C) membagi 2 garis AB menjadi sama panjang yaitu 12 cm untuk menghitung tinggi ΔAPB dengan phytagoras.&nbsp;</p><p>AP sebagai hipotenusa = 15 cm</p><p>AC = BC = 12 cm&nbsp;</p><p>&nbsp;</p><p>AP² = AC² + PC²</p><p>15² = 12² + PC²</p><p>maka</p><p>PC = 9 cm</p><p>&nbsp;</p><p>Luas ΔAPB = ½. 24. 9</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 108 cm²</p><p>&nbsp;</p><p>Luas tembereng = 211,95 - 108</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 103,95 cm²</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p>