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<p><strong>Ingat</strong></p><p>cosec(x)=1/sin(x)</p><p>sec(x)=1/cos(x)</p><ul><li>Maka,</li></ul><p>cosec²B + sec²B = 1/sin²B + 1/cos²B</p><p><strong>samakan penyebutnya</strong></p><p><strong>= cos²B</strong>/(sin²B)<strong>(cos²B)</strong> + <strong>sin²B</strong>/(cos²B)<strong>(sin²B)</strong></p><p>= cos²B+sin²B/(sin²B)(cos²B)</p><p>= [(cos²B+sin²B)/sin²B] × [1/cos²B]</p><p><strong>Ingat&nbsp;</strong></p><p>cos²(x)+sin²(x)= 1</p><ul><li>Maka,</li></ul><p>= [(cos²B+sin²B)/sin²B] × [1/cos²B]</p><p>= [1/sin²B] × [1/cos²B]</p><p>= <strong>cosec²B sec²B</strong></p><p>&nbsp;</p><h2><strong>Jadi terbukti bahwa&nbsp;</strong></h2><p><strong>cosec²B + sec²B=cosec²B sec²B</strong></p>