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Pertanyaan

Vektor a with rightwards harpoon with barb upwards on top space equals space open parentheses table row 2 row cell negative 3 end cell end table close parentheses dicerminkan terhadap sumbu y lalu dirotasikan sejauh 90 searah jarum jam dengan pusat rotasi (-1,2) terjadi vektor b,
maka a with rightwards harpoon with barb upwards on top. b with rightwards harpoon with barb upwards on top = .......... .

  1. 3

  2. 5

  3. 8

  4. -21

  5. -19

R. RGFLSATU

Master Teacher

Jawaban terverifikasi

Pembahasan

a with rightwards arrow on top equals open parentheses table row 2 row cell negative 3 end cell end table close parentheses  • space D i c e r m i n k a n space t e r h a d a p space s u m b u space y  stack a subscript 1 with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row cell negative 3 end cell end table close parentheses  • space R o t a s i colon space minus 900 comma space p u s a t space left parenthesis negative 1.2 right parenthesis  stack b subscript 1 with rightwards arrow on top equals open parentheses table row 0 1 row cell negative 1 end cell 0 end table close parentheses open parentheses table row cell negative 2 plus 1 end cell row cell negative 3 minus 2 end cell end table close parentheses plus open parentheses table row cell negative 1 end cell row 2 end table close parentheses  stack b subscript 1 with rightwards arrow on top equals open parentheses table row 0 1 row cell negative 1 end cell 0 end table close parentheses open parentheses table row cell negative 1 end cell row 5 end table close parentheses plus open parentheses table row cell negative 1 end cell row 2 end table close parentheses equals open parentheses table row cell negative 6 end cell row 3 end table close parentheses  stack a subscript 1 with rightwards arrow on top. stack b subscript 1 with rightwards arrow on top equals negative 12 minus 9 equals negative 21

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