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Untuk reaksi N 2 ​ + 3 H 2 ​ → 2 NH 3 ​ , dt d [ NH 3 ​ ] ​ = 2 × 1 0 − 4 mol L − 1 s − 1 . Nilai dari dt − d [ H 2 ​ ] ​ adalah.…

Untuk reaksi . Nilai dari  adalah.…

  1. 1 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight S to the power of negative 1 end exponent

  2. 2 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight S to the power of negative 1 end exponent

     

  3. 3 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight S to the power of negative 1 end exponent

  4. 4 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight S to the power of negative 1 end exponent

  5. 6 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight S to the power of negative 1 end exponent

     

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Pembahasan

Diketahui Laju reaksi dapat dinyatakan dalam Laju berkurangnya laju pembentukan Laju berkurangnya laju pembentukan

Diketahui

fraction numerator straight d open square brackets NH subscript 3 close square brackets over denominator dt end fraction equals 2 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight s to the power of negative 1 end exponent

Laju reaksi dapat dinyatakan dalam
fraction numerator negative straight d open square brackets straight H subscript 2 close square brackets over denominator dt end fraction equals negative 1 third fraction numerator straight d open square brackets straight H subscript 2 close square brackets over denominator dt end fraction equals 1 half fraction numerator straight d open square brackets NH subscript 3 close square brackets over denominator dt end fraction  
Laju berkurangnya straight N subscript 2 space equals space 1 divided by 2 laju pembentukan NH subscript 3 space equals 1 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight s to the power of negative 1 end exponent

Laju berkurangnya straight H subscript 2 space equals space 3 divided by 2 laju pembentukan NH subscript 3 space equals 3 cross times 10 to the power of negative 4 end exponent space mol space straight L to the power of negative 1 end exponent space straight s to the power of negative 1 end exponent

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