Untuk atom hidrogen pada orbit Bohr n = 2, tentukan jari-jari orbit!

Pertanyaan

Untuk atom hidrogen pada orbit Bohr n = 2, tentukan jari-jari orbit! $begin mathsize 14px style blank to the power of blank end style$

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Pembahasan Video:

Pembahasan Soal:

$begin mathsize 14px style e equals 4 comma 803 cross times 10 to the power of negative 10 end exponent space gr to the power of bevelled 1 half end exponent cm to the power of bevelled 3 over 2 end exponent straight s to the power of negative 1 end exponent m subscript e equals 9 comma 1 cross times 10 to the power of negative 28 end exponent space gr h equals 6 comma 626 cross times 10 to the power of negative 27 end exponent space gr space cm squared space straight s to the power of negative 2 end exponent end style$

Ditanya: r = ...

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row r equals cell fraction numerator h squared over denominator 4 straight pi squared straight e squared straight m subscript straight e end fraction n squared end cell row blank equals cell fraction numerator open parentheses 6 comma 626 cross times 10 to the power of negative 27 end exponent close parentheses squared over denominator 4 open parentheses 3 comma 14 close parentheses squared open parentheses 4 comma 803 cross times 10 to the power of negative 10 end exponent close parentheses squared open parentheses 9 comma 106 cross times 10 to the power of negative 28 end exponent close parentheses end fraction open parentheses 2 close parentheses squared end cell row blank equals cell open parentheses 0 comma 0053 cross times 10 to the power of negative 6 end exponent close parentheses open parentheses 4 close parentheses end cell row blank equals cell open parentheses 5 comma 3 cross times 10 to the power of negative 9 end exponent close parentheses open parentheses 4 close parentheses end cell row blank equals cell 21 comma 2 cross times 10 to the power of negative 9 end exponent space cm end cell row blank equals cell 2 comma 12 space straight A end cell end table end style$

Jadi, jari-jari orbit adalah 2,12 A

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 April 2021

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