UN Fisika 2013 - No.2 Resultan tiga Vektor Perhatikan gambar vektor gaya berikut! Resultan tiga vektor gaya tersebut adalah...

Pertanyaan

UN Fisika 2013 - No.2 Resultan tiga Vektor

Perhatikan gambar vektor gaya berikut!

Resultan tiga vektor gaya tersebut adalah... space

  1. 2 Nspace

  2. begin mathsize 14px style 2 square root of 3 end style Nspace

  3. 5 Nspace

  4. begin mathsize 14px style 5 square root of 3 end style Nspace

  5. 8 Nspace

Y. Maghfirah

Master Teacher

Jawaban terverifikasi

Jawaban

jawabannya adalah B. space

Pembahasan

Pembahasan

Diketahui:

F subscript 1 equals space 14 space straight N space left parenthesis arah space sumbu space x right parenthesis F subscript 2 space equals space 8 square root of 3 space straight N space left parenthesis membentuk space sudut space 30 degree space di space koordinat space left parenthesis negative x comma y right parenthesis right parenthesis F subscript 3 space equals space 10 space straight N space left parenthesis membentuk space sudut space 60 degree space di space koordinat space left parenthesis negative x comma negative y right parenthesis right parenthesis

Ditanyakan : Resultan vektor ... ?

Jawab : 

Resultan dari vektor tersebut adalah:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell begin inline style sum for blank of end style F x end cell equals cell F subscript 1 minus F subscript 2 cos open parentheses 30 degree close parentheses minus F subscript 3 cos open parentheses 60 degree close parentheses end cell row blank equals cell 14 minus 8 square root of 3 1 half square root of 3 minus 10 1 half end cell row blank equals cell 14 minus 12 minus 5 space end cell row blank equals cell negative 3 space straight N end cell end table end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell begin inline style sum for blank of end style F subscript y end cell equals cell F subscript 1 minus F subscript 2 sin open parentheses 30 degree close parentheses plus F subscript 3 sin open parentheses 60 degree close parentheses end cell row blank equals cell 0 minus 8 square root of 3 1 half plus 10 1 half square root of 3 end cell row blank equals cell square root of 3 end cell row blank blank blank end table end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell begin inline style sum for blank of end style F end cell equals cell square root of left parenthesis begin inline style stack sum F subscript x right parenthesis squared plus left parenthesis stack sum F subscript x right parenthesis squared with blank below with blank below end style end root end cell row blank equals cell square root of left parenthesis negative 3 right parenthesis squared plus square root of 3 squared end root end cell row blank equals cell square root of 9 plus 3 end root end cell row blank equals cell square root of 12 space end cell row blank equals cell 2 square root of 3 space straight N end cell end table end style

Oleh karena itu, jawabannya adalah B. space

1rb+

5.0 (5 rating)

Dendi Ciman

Pembahasan lengkap banget

Pertanyaan serupa

Diberikan 3 buah vektor F1= 10 N, F2= 25 N, dan F3= 15 N dengan sudut 37° dan 53° seperti gambar berikut. Tentukan resultan ketiga vektor ! (sin 37∘=3/5, sin 53∘=4/5 )

436

4.6

Jawaban terverifikasi

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