Iklan

Iklan

Pertanyaan

Tentukan titik potong- x dan titik potong- y dari fungsi-fungsi berikut: b. x 2 − 6 x + y + 2 = 0

Tentukan titik potong- dan titik potong- dari fungsi-fungsi berikut:

b. 

Iklan

E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

titik potong- pada adalah .

titik potong-y pada x squared minus 6 x plus y plus 2 equals 0 adalah left parenthesis 0 comma negative 2 right parenthesis.

Iklan

Pembahasan

Akan ditentukan titik potong- , artinya Perhatikan persamaan berikut. maka atau Jadi titik potong- pada adalah . Akan ditentukan titik potong- , artinya maka Jadi titik potong- pada adalah .

Akan ditentukan titik potong-x, artinya y equals 0

Perhatikan persamaan berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 6 x plus y plus 2 end cell equals 0 row cell x squared minus 6 x plus 0 plus 2 end cell equals 0 row cell x squared minus 6 x plus 2 end cell equals 0 end table 

maka

table attributes columnalign right center left columnspacing 0px end attributes row cell x subscript 1 end cell equals cell fraction numerator negative b plus square root of b squared minus 4 a c end root over denominator 2 a end fraction end cell row blank equals cell fraction numerator negative left parenthesis negative 6 right parenthesis plus square root of left parenthesis negative 6 right parenthesis squared minus 4 left parenthesis 1 right parenthesis left parenthesis 2 right parenthesis end root over denominator 2 left parenthesis 1 right parenthesis end fraction end cell row blank equals cell fraction numerator 6 plus square root of 36 minus 8 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 plus square root of 28 over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 plus square root of 4 cross times 7 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 plus 2 square root of 7 over denominator 2 end fraction end cell row blank equals cell 3 plus square root of 7 end cell end table 

atau

table attributes columnalign right center left columnspacing 0px end attributes row cell x subscript 2 end cell equals cell fraction numerator negative b minus square root of b squared minus 4 a c end root over denominator 2 a end fraction end cell row blank equals cell fraction numerator negative left parenthesis negative 6 right parenthesis minus square root of left parenthesis negative 6 right parenthesis squared minus 4 left parenthesis 1 right parenthesis left parenthesis 2 right parenthesis end root over denominator 2 left parenthesis 1 right parenthesis end fraction end cell row blank equals cell fraction numerator 6 minus square root of 36 minus 8 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 minus square root of 28 over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 minus square root of 4 cross times 7 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 6 minus 2 square root of 7 over denominator 2 end fraction end cell row blank equals cell 3 minus square root of 7 end cell end table

Jadi titik potong-x pada x squared minus 6 x plus y plus 2 equals 0 adalah left parenthesis 3 plus square root of 7 comma 0 right parenthesis space atau space open parentheses 3 minus square root of 7 comma 0 close parentheses.

Akan ditentukan titik potong-y, artinya x equals 0

maka

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 6 x plus y plus 2 end cell equals 0 row cell left parenthesis 0 right parenthesis squared minus 6 left parenthesis 0 right parenthesis plus y plus 2 end cell equals 0 row cell 0 minus 0 plus y plus 2 end cell equals 0 row cell y plus 2 end cell equals 0 row y equals cell negative 2 end cell end table 

Jadi titik potong-y pada x squared minus 6 x plus y plus 2 equals 0 adalah left parenthesis 0 comma negative 2 right parenthesis.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

54

Iklan

Iklan

Pertanyaan serupa

Gambarkan sketsa grafik fungsi berikut: b. f ( x ) = − x 2 + 3 x + 10

4

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia