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Tentukan posisi titik  dalam lingkaran dengan pers...

Tentukan posisi titik begin mathsize 14px style open parentheses 4 comma negative 5 close parentheses end style dalam lingkaran dengan persamaan begin mathsize 14px style x squared plus y squared minus 3 x plus y equals 5 squared end style.

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Jawaban:

Substitusi titik begin mathsize 14px style open parentheses 4 comma negative 5 close parentheses end style ke persamaan lingkaran.

begin mathsize 14px style space space space space space space space space space space space space space space space space space space space space space space x squared plus y squared minus 3 x plus y equals 5 squared space space space space space space space space space space space space space space space x squared plus y squared minus 3 x plus y minus 25 equals 0 4 squared plus left parenthesis negative 5 right parenthesis squared minus 3 left parenthesis 4 right parenthesis plus left parenthesis negative 5 right parenthesis minus 25 space midline horizontal ellipsis space 0 space space space space space space space space space space space space space 16 plus 25 minus 12 minus 5 minus 25 space midline horizontal ellipsis space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus 1 less than 0 end style 

Diperoleh begin mathsize 14px style negative 1 less than 0 end style, yang artinya begin mathsize 14px style x squared plus y squared plus straight A x plus straight B y plus straight C less than 0 end style.

Sehingga titik begin mathsize 14px style open parentheses 4 comma negative 5 close parentheses end style tersebut terletak di dalam lingkaran. 

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