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Tentukan pH dari larutan 0,05 M

Tentukan pH dari larutan begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end style  0,05 M begin mathsize 14px style left parenthesis Ka space C H subscript 3 C O O H equals 1 x 10 to the power of negative sign 5 end exponent right parenthesis end style 

Jawaban:

begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end style adalah garam yang bersifat basa yang terbentuk dari asam lemah dan basa kuat.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of Kw over Ka end root x space open square brackets G close square brackets end cell row Kw equals cell tetapan space ionisasi space air space left parenthesis 1 x 10 to the power of negative sign 14 end exponent right parenthesis end cell row Ka equals cell tetapan space asam space lemah end cell row cell open square brackets G close square brackets end cell equals cell konsentrasi space anion space left parenthesis ion space negatif right parenthesis space garam end cell end table end style

begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba yields 2 C H subscript 3 C O O to the power of minus sign and Ba to the power of 2 plus sign 0 comma 05 space M space space space space space space space space space space space space space space space space 0 comma 10 space M space space space space space space space space space space space space 0 comma 05 space M end style 

Konsentrasi anion (ion negatif) garam adalah 0,10 M maka:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of fraction numerator 1 x 10 to the power of negative sign 14 end exponent over denominator 1 x 10 to the power of negative sign 5 end exponent end fraction end root x space 10 to the power of negative sign 1 end exponent end cell row blank equals cell 10 to the power of negative sign 5 end exponent end cell row pOH equals cell negative sign log left parenthesis 10 to the power of negative sign 5 end exponent right parenthesis end cell row blank equals 5 row pH equals cell 14 minus sign 5 end cell row blank equals 9 row blank blank blank end table end style 

Jadi, pH larutan begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end style adalah 9.

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