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Tentukan pH: 4, 9 gram  dalam 500 ml larutan

Tentukan pH:

4, 9 gram begin mathsize 14px style H subscript 2 S O subscript 4 space end style dalam 500 ml larutan

Jawaban:

Berikut adalah tahapan dalam menentukan pH asam kuat begin mathsize 14px style H subscript 2 S O subscript 4 space end style:

begin mathsize 14px style m double bond n space x space Mr n equals m over Mr n equals fraction numerator 4 comma 9 space g over denominator 98 space g forward slash mol end fraction n equals 0 comma 05 mol  end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell n over V end cell row blank equals cell fraction numerator 0 comma 05 space mol over denominator 0 comma 5 space L end fraction end cell row blank equals cell 0 comma 1 space M end cell end table end style 

 

begin mathsize 14px style H subscript 2 S O subscript 4 yields 2 H to the power of plus sign and S O subscript 4 to the power of 2 minus sign end style

Konsentrasi larutan begin mathsize 14px style H subscript 2 S O subscript 4 space end styleadalah 0,1 M maka konsentrasi ion begin mathsize 14px style H to the power of plus sign end style adalah 0,2 M karena jumlah ion begin mathsize 14px style H to the power of plus sign end styleyang dihasilkan adalah 2.

begin mathsize 14px style ion space H to the power of plus sign equals 2 space x space 0 comma 1 space M equals 0 comma 2 space M end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space left parenthesis 2 x 10 to the power of negative sign 1 end exponent right parenthesis end cell row blank equals cell 1 minus sign log space 2 end cell end table end style 

Dengan demikian, pH larutan begin mathsize 14px style H subscript 2 S O subscript 4 space end styleadalah 1-log 2.

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