Iklan

Pertanyaan

Tentukan nilai limit berikut. x → ∞ lim ​ ( 4 x 2 − 8 x + 7 ​ − ( 2 x − 3 ) )

Tentukan nilai limit berikut.

   

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

07

:

10

:

59

Klaim

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

.

 limit as x rightwards arrow infinity of open parentheses square root of 4 x squared minus 8 x plus 7 end root minus open parentheses 2 x minus 3 close parentheses close parentheses equals 1.

Pembahasan

Pembahasan
lock

Jika , maka Maka, hasil limit tersebut: Jadi, .

limit as x rightwards arrow negative infinity of square root of a x squared plus b x plus c end root minus square root of p x squared plus q x plus r end root equals straight L  

Jika a equals p, maka straight L equals fraction numerator b minus q over denominator 2 square root of a end fraction 

Maka, hasil limit tersebut:

limit as x rightwards arrow infinity thin space of open parentheses square root of 4 x squared minus 8 x plus 7 end root minus open parentheses 2 x minus 3 close parentheses close parentheses equals limit as x rightwards arrow infinity thin space of open parentheses square root of 4 x squared minus 8 x plus 7 end root minus square root of open parentheses 2 x minus 3 close parentheses squared end root close parentheses equals limit as x rightwards arrow infinity thin space of open parentheses square root of 4 x squared minus 8 x plus 7 end root minus square root of 4 x squared minus 12 x plus 9 end root close parentheses equals fraction numerator b minus q over denominator 2 square root of a end fraction equals fraction numerator negative 8 minus left parenthesis negative 12 right parenthesis over denominator 2 square root of 4 end fraction equals fraction numerator 4 over denominator 2 times 2 end fraction equals 4 over 4 equals 1 

Jadi, limit as x rightwards arrow infinity of open parentheses square root of 4 x squared minus 8 x plus 7 end root minus open parentheses 2 x minus 3 close parentheses close parentheses equals 1.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

15

Iklan

Pertanyaan serupa

x → ∞ lim ​ 2 x + 3 ​ − x − 2 ​ 2 x − 1 ​ + x + 1 ​ ​ = …

2

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia