Iklan

Pertanyaan

Tentukannilai limit berikut! x → 1 lim ​ 3 x + 1 ​ − 2 x − 1 ​

Tentukan nilai limit berikut!

             

  1. .... 

  2. .... 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

11

:

07

:

58

Klaim

Iklan

L. Rante

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator x minus 1 over denominator square root of 3 x plus 1 end root minus 2 end fraction end cell equals cell limit as x rightwards arrow 1 of open parentheses fraction numerator x minus 1 over denominator square root of 3 x plus 1 end root minus 2 end fraction close parentheses times open parentheses fraction numerator square root of 3 x plus 1 end root plus 2 over denominator square root of 3 x plus 1 end root plus 2 end fraction close parentheses end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses x minus 1 close parentheses open parentheses square root of 3 x plus 1 end root plus 2 close parentheses over denominator open parentheses 3 x plus 1 close parentheses minus open parentheses 4 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis left parenthesis square root of 3 x plus 1 end root plus 2 right parenthesis over denominator 3 x minus 3 end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis left parenthesis square root of 3 x plus 1 end root plus 2 right parenthesis over denominator 3 open parentheses x minus 1 close parentheses end fraction space end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator square root of 3 x plus 1 end root plus 2 over denominator 3 end fraction space end cell row blank equals cell fraction numerator square root of 3 open parentheses 1 close parentheses plus 1 end root plus 2 over denominator 3 end fraction end cell row blank equals cell 4 over 3 end cell end table end style  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

M HAYKAL SYW

Pembahasan lengkap banget

Iklan

Pertanyaan serupa

Tentukan nilai dari x → 3 lim ​ 2 x + 3 ​ x + 1 ​ !

1

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia