Pertanyaan

Tentukan nilai Iimit berikut. x → − 6 lim x + 10 − 2 3 − x − 3

Tentukan nilai Iimit berikut.

$x \to - 6 lim \frac{3 - x - 3}{x + 10 - 2}$

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

$begin mathsize 14px style space space space space space limit as x rightwards arrow negative 6 of fraction numerator square root of 3 minus x end root minus 3 over denominator square root of x plus 10 end root minus 2 end fraction times fraction numerator square root of 3 minus x end root plus 3 over denominator square root of 3 minus x end root plus 3 end fraction times fraction numerator square root of x plus 10 end root plus 2 over denominator square root of x plus 10 end root plus 2 end fraction left right double arrow limit as x rightwards arrow negative 6 of fraction numerator open parentheses 3 minus x minus 9 close parentheses open parentheses square root of x plus 10 end root plus 2 close parentheses over denominator open parentheses x plus 10 minus 4 close parentheses open parentheses square root of 3 minus x end root plus 3 close parentheses end fraction left right double arrow limit as x rightwards arrow negative 6 of fraction numerator negative 6 minus x open parentheses square root of x plus 10 end root plus 2 close parentheses over denominator x plus 6 open parentheses square root of 3 minus x end root plus 3 close parentheses end fraction left right double arrow limit as x rightwards arrow negative 6 of fraction numerator negative open parentheses x plus 6 close parentheses open parentheses square root of x plus 10 end root plus 2 close parentheses over denominator open parentheses x plus 6 close parentheses open parentheses square root of 3 minus x end root plus 3 close parentheses end fraction left right double arrow fraction numerator negative open parentheses square root of negative 6 plus 10 end root plus 2 close parentheses over denominator open parentheses square root of 3 minus open parentheses negative 6 close parentheses end root plus 3 close parentheses end fraction left right double arrow fraction numerator negative 4 over denominator 6 end fraction equals negative 2 over 3 end style$