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Tentukan nilai begin mathsize 14px style k end style agar titik begin mathsize 14px style straight A left parenthesis straight k comma space minus 2 right parenthesis end style terletak pada lingkaran: begin mathsize 14px style straight x squared plus straight y squared minus 5 straight x plus 7 straight y plus 4 equals 0. end style 

R. RGFLLIMA

Master Teacher

Jawaban terverifikasi

Jawaban

 nilai begin mathsize 14px style k end style agar titik begin mathsize 14px style straight A left parenthesis straight k comma space minus 2 right parenthesis end style terletak pada lingkaran: begin mathsize 14px style straight x squared plus straight y squared minus 5 straight x plus 7 straight y plus 4 equals 0 end style adalah begin mathsize 14px style negative 1 end style atau 6.

Pembahasan

Kedudukan titik pada lingkaran.

Titik begin mathsize 14px style straight A left parenthesis straight k comma space minus 2 right parenthesis end style terletak pada lingkaran: begin mathsize 14px style straight x squared plus straight y squared minus 5 straight x plus 7 straight y plus 4 equals 0. end style 

Maka:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight x squared plus straight y squared minus 5 straight x plus 7 straight y plus 4 end cell equals 0 row cell straight k squared plus left parenthesis negative 2 right parenthesis squared minus 5 left parenthesis straight k right parenthesis plus 7 times left parenthesis negative 2 right parenthesis plus 4 end cell equals 0 row cell straight k squared plus 4 minus 5 straight k minus 14 plus 4 end cell equals 0 row cell straight k squared minus 5 straight k minus 6 end cell equals 0 row cell left parenthesis straight k minus 6 right parenthesis left parenthesis straight k plus 1 right parenthesis end cell equals 0 row straight k equals 6 row blank blank atau row straight k equals cell negative 1 end cell end table end style  

Jadi, nilai begin mathsize 14px style k end style agar titik begin mathsize 14px style straight A left parenthesis straight k comma space minus 2 right parenthesis end style terletak pada lingkaran: begin mathsize 14px style straight x squared plus straight y squared minus 5 straight x plus 7 straight y plus 4 equals 0 end style adalah begin mathsize 14px style negative 1 end style atau 6.

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Posisi titik (−5,6) terhadap lingkaran (x+3)2+(y−4)2=9 adalah ....

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