Pertanyaan

Tentukan massa rumus relatif senyawa berikut beserta persentasekadar unsur-unsur penyusunnya. c. Kalium klorat

Tentukan massa rumus relatif senyawa berikut beserta persentase kadar unsur-unsur penyusunnya.

c. Kalium klorat $\;$

I. Solichah

Master Teacher

Jawaban terverifikasi

Jawaban

Mrsenyawa kalium klorat ( ) yaitu 122,5 g/mol dan persentasekadar unsur penyusun senyawa yaitu

Mr senyawa kalium klorat ( K Cl O subscript 3

) yaitu 122,5 g/mol dan persentase kadar unsur penyusun senyawa yaitu K bold equals bold 31 bold comma bold 84 bold percent sign bold comma bold space Cl bold equals bold 28 bold comma bold 98 bold percent sign bold comma bold space O bold equals bold 39 bold comma bold 18 bold percent sign

K bold equals bold 31 bold comma bold 84 bold percent sign bold comma bold space Cl bold equals bold 28 bold comma bold 98 bold percent sign bold comma bold space O bold equals bold 39 bold comma bold 18 bold percent sign

Pembahasan

Rumus molekul Kalium klorat = Diketahui K = 39, Cl = 35,5, O = 16, sehingga : Menentukan kadar unsur-unsur penyusunnya: Jadi, Mrsenyawa kalium klorat ( ) yaitu 122,5 g/mol dan persentasekadar unsur penyusun senyawa yaitu

Rumus molekul Kalium klorat = K Cl O subscript 3

Diketahui italic A subscript r K = 39, Cl = 35,5, O = 16, sehingga italic M subscript r space K Cl O subscript 3 :

Menentukan kadar unsur-unsur penyusunnya:

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign K end cell equals cell fraction numerator 1 cross times italic A subscript r space K over denominator italic M subscript r space K Cl O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 39 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 39 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell bold 31 bold comma bold 84 bold percent sign end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign Cl end cell equals cell fraction numerator 1 cross times italic A subscript r space Cl over denominator italic M subscript r space K Cl O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 1 cross times 35 comma 5 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 35 comma 5 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell bold 28 bold comma bold 98 bold percent sign end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign O end cell equals cell fraction numerator 3 cross times italic A subscript r space O over denominator italic M subscript r space K Cl O subscript 3 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 3 cross times 16 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 48 over denominator 122 comma 5 end fraction cross times 100 percent sign end cell row blank equals cell bold 39 bold comma bold 18 bold percent sign end cell end table$

Jadi, Mr senyawa kalium klorat () yaitu 122,5 g/mol dan persentase kadar unsur penyusun senyawa yaitu