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Tentukan massa rumus relatif senyawa berikut beserta persentasekadar unsur-unsur penyusunnya. d. Besi(ll) fosfat

Tentukan massa rumus relatif senyawa berikut beserta persentase kadar unsur-unsur penyusunnya.

d. Besi(ll) fosfat $\;$ space

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Habis dalam

Klaim

A. Chandra

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

jawaban yang benar sesuai penjelasan diatas.

Pembahasan

Rumus molekul Besi(ll) fosfat = Diketahui Fe = 56, P = 31, O = 16, sehingga : Menentukan kadar unsur-unsur penyusunnya: Jadi, jawaban yang benar sesuai penjelasan diatas.

Rumus molekul Besi(ll) fosfat = Fe subscript 3 open parentheses P O subscript 4 close parentheses subscript 2

Diketahui italic A subscript r Fe = 56, P = 31, O = 16, sehingga italic M subscript r space Fe subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 :

Menentukan kadar unsur-unsur penyusunnya:

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign Fe end cell equals cell fraction numerator 3 cross times italic A subscript r space Fe over denominator italic M subscript r space Fe subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 3 cross times 56 over denominator 358 end fraction cross times 100 percent sign end cell row blank equals cell 168 over 358 cross times 100 percent sign end cell row blank equals cell bold 46 bold comma bold 92 bold percent sign end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign P end cell equals cell fraction numerator 2 cross times italic A subscript r space P over denominator italic M subscript r space Fe subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 cross times 31 over denominator 358 end fraction cross times 100 percent sign end cell row blank equals cell 62 over 358 cross times 100 percent sign end cell row blank equals cell bold 17 bold comma bold 32 bold percent sign end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell bold percent sign O end cell equals cell fraction numerator 8 cross times italic A subscript r space O over denominator italic M subscript r space Fe subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 8 cross times 16 over denominator 358 end fraction cross times 100 percent sign end cell row blank equals cell 128 over 358 cross times 100 percent sign end cell row blank equals cell bold 35 bold comma bold 75 bold percent sign end cell end table$

Jadi, jawaban yang benar sesuai penjelasan diatas.