Roboguru

Tentukan kelarutan  () dalam 500 ml  0,1 M!

Pertanyaan

Tentukan kelarutan Ag Br (K subscript sp equals 5 cross times 10 to the power of negative sign 13 end exponent) dalam 500 ml Ag N O subscript 3 0,1 M!

  1. ...space 

  2. ...space 

Pembahasan Soal:

Kelarutan Ag N O subscript 3
 equals n over V equals fraction numerator 0 comma 1 space mol over denominator 0 comma 5 space L end fraction equals 0 comma 2 space M 

Ag N O subscript 3 equilibrium Ag to the power of plus sign and N O subscript 3 to the power of minus sign 0 comma 2 space M space space space space space 0 comma 2 M space space space 0 comma 2 M 

Kelarutan Ag Br dalam air:

Ag Br equilibrium Ag to the power of plus sign and Br to the power of minus sign s space M space space space space space space s space M space space space space space s space M 

Kelarutan Ag Br dalam larutan Ag N O subscript 3:

K subscript sp space Ag Br double bond open square brackets Ag to the power of plus sign close square brackets open square brackets Br to the power of minus sign close square brackets 5 cross times 10 to the power of negative sign 13 end exponent equals left parenthesis 0 comma 2 right parenthesis point s space space space space space space space space space space space space space s equals fraction numerator 5 cross times 10 to the power of negative sign 13 end exponent over denominator 0 comma 2 end fraction space space space space space space space space space space space space space space space equals 2 comma 5 cross times 10 to the power of negative sign 14 end exponent space M 

Jadi, kelarutan  Ag Br dalam larutan Ag N O subscript 3 adalah 2 comma 5 cross times 10 to the power of negative sign 14 end exponent space M.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Juni 2021

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