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Tentukan kelarutan AgBr ( K sp ​ = 5 × 1 0 − 13 ) dalam 5 liter CaBr 2 ​ 1 mol!

Tentukan kelarutan  () dalam 5 liter  1 mol!

  1. ...space 

  2. ...space 

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R. Anisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

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kelarutan dalam larutan tersebut adalah .

kelarutan Ag Br dalam larutan Ca Br subscript 2 tersebut adalah 1 comma 25 cross times 10 to the power of negative sign 14 end exponent space M.

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Kelarutan : Jadi, kelarutan dalam larutan tersebut adalah .

open square brackets Ca Br subscript 2 close square brackets equals n over V space space space space space space space space space equals fraction numerator 1 space mol over denominator 5 space L end fraction space space space space space space space space space equals 0 comma 2 space M Ca Br subscript 2 equilibrium Ca to the power of 2 plus sign and 2 Br to the power of minus sign 0 comma 2 space M space space space space 0 comma 2 M space space space space space 0 comma 4 M 

Kelarutan  Ag Br:

Ag Br equilibrium Ag to the power of plus sign and Br to the power of minus sign s space M space space space space space space s space M space space space space space s space M 

K subscript sp space Ag Br double bond open square brackets Ag to the power of plus sign close square brackets open square brackets Br to the power of minus sign close square brackets 5 cross times 10 to the power of negative sign 13 end exponent equals s point left parenthesis 0 comma 4 right parenthesis space space space space space space space space space space space space s equals fraction numerator 5 cross times 10 to the power of negative sign 13 end exponent over denominator 0 comma 4 end fraction space space space space space space space space space space space space space space equals 1 comma 25 cross times 10 to the power of negative sign 14 end exponent space M 

Jadi, kelarutan Ag Br dalam larutan Ca Br subscript 2 tersebut adalah 1 comma 25 cross times 10 to the power of negative sign 14 end exponent space M.

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