Iklan

Iklan

Pertanyaan

Tentukan hasil perkalian akar-akar bilangan berikut! b. ( 4 2 ​ − 3 ​ ) ( 4 2 ​ + 8 ​ )

Tentukan hasil perkalian akar-akar bilangan berikut!

b.   

Iklan

E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

hasil dari adalah .

hasil dari open parentheses 4 square root of 2 minus square root of 3 close parentheses open parentheses fourth root of 2 plus square root of 8 close parentheses adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fourth root of 8 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fourth root of 18 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 16 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 6 end cell end table.

Iklan

Pembahasan

Ingat kembali rumus berikut. Dari rumus di atas, diperoleh perhitungan sebagai berikut. Jadi, hasil dari adalah .

Ingat kembali rumus berikut.

  • table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses square root of a minus square root of b close parentheses open parentheses square root of c plus square root of d close parentheses end cell equals cell open parentheses square root of a close parentheses open parentheses square root of c close parentheses minus open parentheses square root of b close parentheses open parentheses square root of c close parentheses plus open parentheses square root of a close parentheses open parentheses square root of d close parentheses minus open parentheses square root of b close parentheses open parentheses square root of d close parentheses end cell end table
  • square root of a cross times square root of b equals square root of a cross times b end root 
  • square root of a squared cross times b end root equals a square root of b 
  • square root of a equals fourth root of a squared end root 

Dari rumus di atas, diperoleh perhitungan sebagai berikut.

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses 4 square root of 2 minus square root of 3 close parentheses open parentheses fourth root of 2 plus square root of 8 close parentheses end cell row blank equals cell open parentheses 4 square root of 2 close parentheses open parentheses fourth root of 2 close parentheses minus open parentheses square root of 3 close parentheses open parentheses fourth root of 2 close parentheses plus open parentheses 4 square root of 2 close parentheses open parentheses square root of 8 close parentheses minus open parentheses square root of 3 close parentheses open parentheses square root of 8 close parentheses end cell row blank equals cell 4 times open parentheses fourth root of 2 squared end root close parentheses open parentheses fourth root of 2 close parentheses minus open parentheses fourth root of 3 squared end root close parentheses open parentheses fourth root of 2 close parentheses plus 4 square root of 2 cross times 8 end root minus square root of 3 cross times 8 end root end cell row blank equals cell 4 times fourth root of 2 squared times 2 end root minus fourth root of 3 squared times 2 end root plus 4 square root of 16 minus square root of 24 end cell row blank equals cell 4 fourth root of 8 minus fourth root of 18 plus 4 times 4 minus square root of 2 squared times 6 end root end cell row blank equals cell 4 fourth root of 8 minus fourth root of 18 plus 16 minus 2 square root of 6 end cell end table 

Jadi, hasil dari open parentheses 4 square root of 2 minus square root of 3 close parentheses open parentheses fourth root of 2 plus square root of 8 close parentheses adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fourth root of 8 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fourth root of 18 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 16 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 6 end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

43

Iklan

Iklan

Pertanyaan serupa

Tentukan hasil perkalian akar-akar bilangan berikut! c. ( 6 ​ + 5 ​ ) ( 2 6 ​ − 2 ​ )

105

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia