Pertanyaan

Tentukan hasil pemangkatan berikut! g. ( − 5 x 3 y 5 ) − 4 h. ( − 4 x − 5 y 4 ) − 5

Tentukan hasil pemangkatan berikut!

g. $(- 5 x^{3} y^{5})^{- 4}$
h. $(- 4 x^{- 5} y^{4})^{- 5}$

D. Nuryani

Master Teacher

Mahasiswa/Alumni Universitas Padjadjaran

Jawaban terverifikasi

Jawaban

hasil dari , dan .

hasil dari $open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table$ , dan $open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table$ .

Pembahasan

Ingatlah sifat-sifat bilangan berpangkat berikut. Berdasarkan sifat-sifat di atas, maka: g) h) Dengan demikian, hasil dari , dan .

Ingatlah sifat-sifat bilangan berpangkat berikut.

Berdasarkan sifat-sifat di atas, maka:

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent end cell equals cell 1 over open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of 4 end cell row blank equals cell fraction numerator 1 over denominator open parentheses negative 5 close parentheses to the power of 4 times open parentheses x cubed close parentheses to the power of 4 times open parentheses y to the power of 5 close parentheses to the power of 4 end fraction end cell row blank equals cell fraction numerator 1 over denominator 5 to the power of 4 times x to the power of 12 times y to the power of 20 end fraction end cell row blank equals cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent end cell equals cell 1 over open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of 5 end cell row blank equals cell 1 over open parentheses negative begin display style fraction numerator 4 y to the power of 4 over denominator x to the power of 5 end fraction end style close parentheses to the power of 5 end cell row blank equals cell fraction numerator 1 over denominator negative open parentheses fraction numerator 4 y to the power of 4 over denominator x to the power of 5 end fraction close parentheses to the power of 5 end fraction end cell row blank equals cell negative fraction numerator 1 over denominator begin display style open parentheses 4 y to the power of 4 close parentheses to the power of 5 over open parentheses x to the power of 5 close parentheses to the power of 5 end style end fraction end cell row blank equals cell negative open parentheses x to the power of 5 close parentheses to the power of 5 over open parentheses 4 y to the power of 4 close parentheses to the power of 5 end cell row blank equals cell negative fraction numerator x to the power of 25 over denominator 4 to the power of 5 y to the power of 20 end fraction end cell row blank equals cell negative fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table$

Dengan demikian, hasil dari $open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table$ , dan $open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table$ .