Roboguru

Pertanyaan

Tentukan hasil pemangkatan berikut!

g. open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent
h. open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent

D. Nuryani

Master Teacher

Mahasiswa/Alumni Universitas Padjadjaran

Jawaban terverifikasi

Jawaban

hasil dari  open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table, dan open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table.

Pembahasan

Ingatlah sifat-sifat bilangan berpangkat berikut.

left parenthesis straight i right parenthesis space open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent left parenthesis ii right parenthesis space open parentheses a b close parentheses to the power of m equals a to the power of m b to the power of m left parenthesis iii right parenthesis space open parentheses a divided by b close parentheses to the power of m equals a to the power of m divided by b to the power of m left parenthesis iv right parenthesis space a to the power of negative m end exponent equals 1 over a to the power of m left parenthesis straight v right parenthesis space open parentheses negative a close parentheses to the power of m equals a to the power of m space space untuk space m space bil. genap left parenthesis vi right parenthesis space open parentheses negative a close parentheses to the power of m equals negative a to the power of m space space untuk space m space bil. ganjil    

Berdasarkan sifat-sifat di atas, maka:

g)

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent end cell equals cell 1 over open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of 4 end cell row blank equals cell fraction numerator 1 over denominator open parentheses negative 5 close parentheses to the power of 4 times open parentheses x cubed close parentheses to the power of 4 times open parentheses y to the power of 5 close parentheses to the power of 4 end fraction end cell row blank equals cell fraction numerator 1 over denominator 5 to the power of 4 times x to the power of 12 times y to the power of 20 end fraction end cell row blank equals cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table

h)

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent end cell equals cell 1 over open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of 5 end cell row blank equals cell 1 over open parentheses negative begin display style fraction numerator 4 y to the power of 4 over denominator x to the power of 5 end fraction end style close parentheses to the power of 5 end cell row blank equals cell fraction numerator 1 over denominator negative open parentheses fraction numerator 4 y to the power of 4 over denominator x to the power of 5 end fraction close parentheses to the power of 5 end fraction end cell row blank equals cell negative fraction numerator 1 over denominator begin display style open parentheses 4 y to the power of 4 close parentheses to the power of 5 over open parentheses x to the power of 5 close parentheses to the power of 5 end style end fraction end cell row blank equals cell negative open parentheses x to the power of 5 close parentheses to the power of 5 over open parentheses 4 y to the power of 4 close parentheses to the power of 5 end cell row blank equals cell negative fraction numerator x to the power of 25 over denominator 4 to the power of 5 y to the power of 20 end fraction end cell row blank equals cell negative fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table

Dengan demikian, hasil dari  open parentheses negative 5 x cubed y to the power of 5 close parentheses to the power of negative 4 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator 625 x to the power of 12 y to the power of 20 end fraction end cell end table, dan open parentheses negative 4 x to the power of negative 5 end exponent y to the power of 4 close parentheses to the power of negative 5 end exponent equals table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x to the power of 25 over denominator 1.024 y to the power of 20 end fraction end cell end table.

46

0.0 (0 rating)

Pertanyaan serupa

Tentukan hasil pemangkatan berikut! d. (−5a−2)−3 e. (2a2b3)−6 f. (3a3b−4)−5

84

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia