Pertanyaan

Tentukan hasil pemangkatan berikut! a. ( 3 2 ) − 4 b. ( − 2 2 ) − 2 c. ( 4 a − 3 ) − 3

Tentukan hasil pemangkatan berikut!

a. $(3^{2})^{- 4}$
b. $(- 2^{2})^{- 2}$
c. $(4 a^{- 3})^{- 3}$

D. Nuryani

Master Teacher

Mahasiswa/Alumni Universitas Padjadjaran

Jawaban terverifikasi

Jawaban

hasil dari , , dan .

hasil dari $open parentheses 3 squared close parentheses to the power of negative 4 end exponent equals fraction numerator 1 over denominator 6.561 end fraction$ , open parentheses negative 2 squared close parentheses to the power of negative 2 end exponent equals 1 over 16

open parentheses negative 2 squared close parentheses to the power of negative 2 end exponent equals 1 over 16

, dan

open parentheses 4 a to the power of negative 3 end exponent close parentheses to the power of negative 3 end exponent equals a to the power of 9 over 64

Pembahasan

Ingatlah sifat-sifat bilangan berpangkat berikut. Berdasarkan sifat-sifat di atas, maka: a) b) c) Dengan demikian, hasil dari , , dan .

Ingatlah sifat-sifat bilangan berpangkat berikut.

Berdasarkan sifat-sifat di atas, maka:

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 3 squared close parentheses to the power of negative 4 end exponent end cell equals cell 3 to the power of 2 cross times open parentheses negative 4 close parentheses end exponent end cell row blank equals cell 3 to the power of negative 8 end exponent end cell row blank equals cell 1 over 3 to the power of 8 end cell row blank equals cell fraction numerator 1 over denominator 6.561 end fraction end cell end table$

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 4 a to the power of negative 3 end exponent close parentheses to the power of negative 3 end exponent end cell equals cell 1 over open parentheses 4 a to the power of negative 3 end exponent close parentheses cubed end cell row blank equals cell 1 over open parentheses begin display style 4 over a cubed end style close parentheses cubed end cell row blank equals cell fraction numerator 1 over denominator open parentheses 4 over a cubed close parentheses cross times open parentheses 4 over a cubed close parentheses cross times open parentheses 4 over a cubed close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator begin display style 64 over a to the power of 3 plus 3 plus 3 end exponent end style end fraction end cell row blank equals cell fraction numerator 1 over denominator begin display style 64 over a to the power of 9 end style end fraction end cell row blank equals cell a to the power of 9 over 64 end cell end table$

Dengan demikian, hasil dari $open parentheses 3 squared close parentheses to the power of negative 4 end exponent equals fraction numerator 1 over denominator 6.561 end fraction$ , open parentheses negative 2 squared close parentheses to the power of negative 2 end exponent equals 1 over 16 , dan open parentheses 4 a to the power of negative 3 end exponent close parentheses to the power of negative 3 end exponent equals a to the power of 9 over 64 .