Pertanyaan

Tentukan hasil operasi hitung bentuk aljabar berikut! 56 x 7 y 6 : ( − 4 x 4 y 5 : 2 x 2 y 4 )

Tentukan hasil operasi hitung bentuk aljabar berikut!

$56 x^{7} y^{6} : (- 4 x^{4} y^{5} : 2 x^{2} y^{4})$

Y. Fathoni

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta.

Jawaban terverifikasi

Jawaban

diperoleh hasil operasi hitung bentuk aljabar adalah .

diperoleh hasil operasi hitung bentuk aljabar 56 x to the power of 7 y to the power of 6 space colon space open parentheses negative 4 x to the power of 4 y to the power of 5 space colon space 2 x squared y to the power of 4 close parentheses

56 x to the power of 7 y to the power of 6 space colon space open parentheses negative 4 x to the power of 4 y to the power of 5 space colon space 2 x squared y to the power of 4 close parentheses

adalah

negative 28 x to the power of 5 y to the power of 5

Pembahasan

Gunakan konsep pembagian dua bentuk aljabar dengan menggunakan faktor yang sama. Perhatikan perhitungan berikut. Jadi, diperoleh hasil operasi hitung bentuk aljabar adalah .

Gunakan konsep pembagian dua bentuk aljabar dengan menggunakan faktor yang sama.

Perhatikan perhitungan berikut.

$table attributes columnalign right center left columnspacing 2px end attributes row cell 56 x to the power of 7 y to the power of 6 space colon space open parentheses negative 4 x to the power of 4 y to the power of 5 space colon space 2 x squared y to the power of 4 close parentheses end cell equals cell 56 x to the power of 7 y to the power of 6 space colon space fraction numerator negative 4 x to the power of 4 y to the power of 5 over denominator 2 x squared y to the power of 4 end fraction end cell row blank equals cell 56 x to the power of 7 y to the power of 6 space colon space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses open parentheses x to the power of 4 over x squared close parentheses open parentheses y to the power of 5 over y to the power of 4 close parentheses end cell row blank equals cell 56 x to the power of 7 y to the power of 6 space colon space open parentheses negative 2 x squared y close parentheses end cell row blank equals cell fraction numerator 56 x to the power of 7 y to the power of 6 over denominator negative 2 x squared y end fraction end cell row blank equals cell open parentheses fraction numerator 56 over denominator negative 2 end fraction close parentheses open parentheses x to the power of 7 over x squared close parentheses open parentheses y to the power of 6 over y close parentheses end cell row blank equals cell negative 28 open parentheses x to the power of 5 close parentheses open parentheses y to the power of 5 close parentheses end cell row blank equals cell negative 28 x to the power of 5 y to the power of 5 end cell end table$

Jadi, diperoleh hasil operasi hitung bentuk aljabar 56 x to the power of 7 y to the power of 6 space colon space open parentheses negative 4 x to the power of 4 y to the power of 5 space colon space 2 x squared y to the power of 4 close parentheses adalah negative 28 x to the power of 5 y to the power of 5 .