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Tentukan derajat keasamaan (pH) suatu asam  dan suatu basa !

Pertanyaan

Tentukan derajat keasamaan (pH) suatu asam begin mathsize 14px style bold HA bold space bold 0 bold comma bold 01 bold space italic M bold space bold left parenthesis K subscript italic a bold equals bold 10 to the power of bold minus sign bold 4 end exponent bold right parenthesis end style dan suatu basa begin mathsize 14px style B O H bold space bold 0 bold comma bold 1 bold space italic M bold space bold left parenthesis K subscript italic b bold equals bold 10 to the power of bold minus sign bold 3 end exponent bold right parenthesis end styleundefined 

Pembahasan Soal:

Menentukan pH dari HA

HA adalah asam lemah karena memilki nila begin mathsize 14px style K subscript a equals 10 to the power of negative sign 4 end exponent end style, maka dapat diselesaikan sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M subscript a end root end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of 10 to the power of negative sign 4 end exponent cross times 10 to the power of negative sign 2 end exponent end root end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of 10 to the power of negative sign 6 end exponent end root end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 3 end exponent space M end cell row blank blank blank row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log left square bracket 10 to the power of negative sign 3 end exponent right square bracket end cell row pH equals 3 end table end style 

Jadi pH dari HA 0,01 M adalah 3.
 

Menentukan pH dari BOH

BOH adalah basa lemah karena memilki nilai begin mathsize 14px style K subscript italic b equals 10 to the power of negative sign 3 end exponent end style, maka dapat diselesaikan sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript b cross times M subscript b end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of 10 to the power of negative sign 3 end exponent cross times 10 to the power of negative sign 1 end exponent end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of 10 to the power of negative sign 4 end exponent end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 2 end exponent end cell row blank blank blank row pOH equals cell negative sign log open square brackets O H to the power of minus sign close square brackets end cell row pOH equals cell negative sign log left square bracket 10 to the power of negative sign 2 end exponent right square bracket end cell row pOH equals 2 row pH equals cell 14 minus sign pOH end cell row pH equals cell 14 minus sign 2 end cell row pH equals 12 end table end style 

Jadi pH dari BOH 0,1 M adalah 12.undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 April 2021

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