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Tentukan [ H + ] dan [ OH − ] dalam larutan yang nilai pH-nya: 4,3 (diketahui log 5 = 0,7)

Tentukan  dan  dalam larutan yang nilai pH-nya:

4,3 (diketahui log 5 = 0,7)space

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N. Puspita

Master Teacher

Jawaban terverifikasi

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dan dalam larutan tersebut secara berturut-turut yaitu dan .

open square brackets H to the power of plus sign close square brackets dan open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut secara berturut-turut yaitu 5 cross times 10 to the power of negative sign 5 end exponent space M dan 2 cross times 10 to the power of negative sign 10 end exponent space M.space 

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Pembahasan

Pembahasan
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Besarnya konsentrasi ion dapat ditentukan dengan cara sebagai berikut. Sementara konsentrasi ion dalam larutan tersebut yaitu : Jadi, dan dalam larutan tersebut secara berturut-turut yaitu dan .

Besarnya konsentrasi ion open square brackets H to the power of plus sign close square brackets dapat ditentukan dengan cara sebagai berikut.


table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell 4 comma 3 end cell equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell left parenthesis 5 minus sign 0 comma 7 right parenthesis end cell equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell negative sign antilog left parenthesis 5 minus sign 0 comma 7 right parenthesis end cell row blank equals cell negative sign antilog left parenthesis 5 minus sign log space 5 right parenthesis end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times 5 end cell row blank equals cell 5 cross times 10 to the power of negative sign 5 end exponent space M end cell end table


Sementara konsentrasi ion open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut yaitu :


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell 10 to the power of negative sign 14 end exponent end cell row blank blank blank row cell open square brackets H to the power of plus sign close square brackets middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript w end cell row cell left parenthesis 5 cross times 10 to the power of negative sign 5 end exponent right parenthesis middle dot open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row blank equals cell 0 comma 2 cross times 10 to the power of negative sign 9 end exponent end cell row blank equals cell 2 cross times 10 to the power of negative sign 10 end exponent space M end cell end table


Jadi, open square brackets H to the power of plus sign close square brackets dan open square brackets O H to the power of minus sign close square brackets dalam larutan tersebut secara berturut-turut yaitu 5 cross times 10 to the power of negative sign 5 end exponent space M dan 2 cross times 10 to the power of negative sign 10 end exponent space M.space 

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