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Tentukan berapa gram  yang harus ditambahkan kedalam 100 mL  0,1 M () agar dihasilkan larutan penyangga dengan pH 5 - log 2 ... ()

Pertanyaan

Tentukan berapa gram open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca yang harus ditambahkan kedalam 100 mL C H subscript 3 C O O H 0,1 M (K subscript a equals 10 to the power of negative sign 5 end exponent) agar dihasilkan larutan penyangga dengan pH 5 - log 2 ... (italic M subscript r space open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca equals 158)

  1. 0,79 space 

  2. 0,85 space 

  3. 0,96 space 

  4. 1,14 space 

  5. 3,54 space 

Pembahasan Soal:

Menentukan konsentrasi ion H to the power of plus sign:

table attributes columnalign right center left columnspacing 0px end attributes row cell italic p H end cell equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell 5 minus sign log space 2 end cell equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell negative sign log space 2 cross times 10 to the power of negative sign 5 end exponent end cell equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 2 cross times 10 to the power of negative sign 5 end exponent space M end cell end table 

Menentukan massa open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell Ka cross times n subscript C H subscript 3 C O O H end subscript over n subscript C H subscript 3 C O O Ca end subscript end cell row cell 2 cross times 10 to the power of negative sign 5 end exponent end cell equals cell 10 to the power of negative sign 5 end exponent cross times fraction numerator 0 comma 1 cross times 0 comma 1 over denominator n subscript C H subscript 3 C O O Ca end subscript end fraction end cell row cell n subscript C H subscript 3 C O O Ca end subscript end cell equals cell fraction numerator 0 comma 01 over denominator 2 end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 3 end exponent space mol end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 5 cross times 10 to the power of negative sign 3 end exponent cross times 158 end cell row blank equals cell 0 comma 79 space gram end cell end table 

Oleh karena itu, massa open parentheses C H subscript 3 C O O close parentheses subscript 2 Ca adalah 0,79 gram.

Jadi, jawaban yang benar adalah A.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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