Pertanyaan

Tentukan bentuk sederhana dari cos 2 0 ∘ sec 4 0 ∘ tan 13 0 ∘ sin 7 0 ∘ sec 14 0 ∘ tan 5 0 ∘ = ...

Tentukan bentuk sederhana dari $\frac{sin 7 0 ^{\circ} sec 14 0 ^{\circ} tan 5 0 ^{\circ}}{cos 2 0 ^{\circ} sec 4 0 ^{\circ} tan 13 0 ^{\circ}} = ...$

A. Acfreelance

Master Teacher

Mahasiswa/Alumni UIN Walisongo Semarang

Jawaban terverifikasi

Jawaban

hasil dari

hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin 70 degree sec 140 degree tan 50 degree over denominator cos 20 degree sec 40 degree tan 130 degree end fraction end cell equals 1 end table$

Pembahasan

Jadi hasil dari

$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin 70 degree sec 140 degree tan 50 degree over denominator cos 20 degree sec 40 degree tan 130 degree end fraction end cell equals cell fraction numerator sin left parenthesis 90 minus 20 right parenthesis cross times sec left parenthesis 180 minus 40 right parenthesis cross times tan 50 over denominator cos 20 cross times sec 40 cross times tan open parentheses 180 minus 30 close parentheses end fraction end cell row blank equals cell fraction numerator cos 20 cross times negative sec 40 cross times tan 50 over denominator cos 20 cross times sec 40 cross times negative tan 50 end fraction end cell row blank equals 1 end table$

Jadi hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin 70 degree sec 140 degree tan 50 degree over denominator cos 20 degree sec 40 degree tan 130 degree end fraction end cell equals 1 end table$