Suatu kawat berarus listrik dilengkungkan seperti ...

Suatu kawat berarus listrik dilengkungkan seperti gambar. Jika jari-jari lengkungan a = 30 cm, maka besarnya induksi magnetik di pusat lingkaran adalah .... $open parentheses mu subscript 0 equals 4 pi space x space 10 to the power of 7 space W b. m to the power of negative 1 end exponent A to the power of negative 1 end exponent close parentheses$

$0 comma 83 pi space x space 10 to the power of negative 7 end exponent space T$
$2 comma 50 pi space x space 10 to the power of negative 7 end exponent space T$
$3 comma 30 pi space x space 10 to the power of negative 7 end exponent space T$
$3 comma 30 pi space x space 10 to the power of negative 5 end exponent space T$
$2 comma 50 pi space x space 10 to the power of negative 5 end exponent space T$

Jawaban:

Diketahui :

$straight I equals 0 comma 5 space straight A straight a equals 30 space cm equals 0 comma 3 space straight m$

Maka besarnya induksi magnetik di titik P adalah

$B equals fraction numerator open parentheses 360 to the power of o minus 90 to the power of o close parentheses over denominator open parentheses 360 to the power of o close parentheses end fraction x fraction numerator mu subscript 0 I over denominator 2 a end fraction B equals 270 to the power of o over 360 to the power of o x fraction numerator open parentheses 4 pi space x space 10 to the power of negative 7 end exponent close parentheses open parentheses 0 comma 5 close parentheses over denominator open parentheses 2 close parentheses open parentheses 0 comma 3 close parentheses end fraction B equals 3 over 4 x fraction numerator 2 pi space x space 10 to the power of negative 7 end exponent over denominator 0 comma 6 end fraction B equals 2 comma 5 pi space x space 10 to the power of negative 7 end exponent T$

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