Roboguru

Suatu berkas sinar-X dengan energi 50 eV mengalami hamburan Compton dengan sudut 90°. Tentukan energi foton sinar-X sesudah dihamburkan (, ). Tips: energi foton dirumuskan oleh

Pertanyaan

Suatu berkas sinar-X dengan energi 50 eV mengalami hamburan Compton dengan sudut 90°. Tentukan energi foton sinar-X sesudah dihamburkan (begin mathsize 14px style h equals 6 comma 60.10 to the power of negative 34 end exponent space Js end style, begin mathsize 14px style m subscript e equals 9 comma 0 space. space 10 to the power of negative 31 end exponent space kg end style).
Tips: energi foton dirumuskan oleh begin mathsize 14px style E equals h c divided by lambda end style 

Pembahasan Soal:

begin mathsize 14px style E equals 50 space eV 1 space e V equals 1 comma 6 cross times 10 to the power of negative 19 end exponent space straight J theta equals 90 degree h equals 6 comma 60 cross times 10 to the power of negative 34 end exponent space Js m subscript e equals 9 comma 0 cross times 10 to the power of negative 31 end exponent space kg end style 

Ditanyakan: energi foton sesudah dihamburkan?
Jawab:

Cari panjang gelombang mula-mula
begin mathsize 14px style E equals h c over lambda lambda equals fraction numerator h c over denominator E end fraction lambda equals fraction numerator open parentheses 6 comma 60 cross times 10 to the power of negative 34 end exponent close parentheses open parentheses 3 cross times 10 to the power of 8 close parentheses over denominator 50 cross times 1 comma 6 cross times 10 to the power of negative 19 end exponent end fraction lambda equals fraction numerator 19 comma 8 cross times 10 to the power of negative 26 end exponent over denominator 80 cross times 10 to the power of negative 19 end exponent end fraction lambda equals 0 comma 2475 cross times 10 to the power of negative 7 end exponent space straight m end style 

Maka setelah mengalami hamburan Compton
begin mathsize 14px style lambda apostrophe minus lambda equals fraction numerator h over denominator m subscript e c end fraction open parentheses 1 minus cos 90 close parentheses lambda apostrophe equals 0 comma 2475 cross times 10 to the power of negative 7 end exponent plus fraction numerator 6 comma 60 cross times 10 to the power of negative 34 end exponent over denominator open parentheses 9 cross times 10 to the power of negative 31 end exponent close parentheses open parentheses 3 cross times 10 to the power of 8 close parentheses end fraction open parentheses 1 close parentheses lambda apostrophe equals 0 comma 2475 cross times 10 to the power of negative 7 end exponent plus 0 comma 2444 cross times 10 to the power of negative 11 end exponent lambda apostrophe equals 2475 cross times 10 to the power of negative 11 end exponent plus 0 comma 2444 cross times 10 to the power of negative 11 end exponent lambda apostrophe equals 2475 comma 24 cross times 10 to the power of negative 11 end exponent space straight m end style 

Energi setelah hamburan
begin mathsize 14px style E apostrophe equals h fraction numerator c over denominator lambda apostrophe end fraction E apostrophe equals fraction numerator open parentheses 6 comma 60 cross times 10 to the power of negative 34 end exponent close parentheses open parentheses 3 cross times 10 to the power of 8 close parentheses over denominator open parentheses 2475 comma 24 cross times 10 to the power of negative 11 end exponent close parentheses end fraction E apostrophe equals 79 cross times 10 to the power of negative 19 end exponent space straight J end style 

Jadi, energi foton sesudah dihamburkan adalah begin mathsize 14px style bold 79 bold cross times bold 10 to the power of bold minus bold 19 end exponent bold space bold J end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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