Iklan

Pertanyaan

Siwon memiliki 3 jenis larutan, yaitularutan A, B, dan C. Jika ketiga larutan memiliki konsentrasi 1 M dan pH larutan secara berurutanadalah 3 – log 5, 3 – log 3, dan 3 – log 4, urutan kekuatan asam yang bersifat paling kuat ke lemah berdasarkan nilai tetapan kesetimbangan asam adalah ....

Siwon memiliki 3 jenis larutan, yaitu larutan A, B, dan C. Jika ketiga larutan memiliki konsentrasi 1 M dan pH larutan secara berurutan adalah 3 – log 5, 3 – log 3, dan 3 – log 4, urutan kekuatan asam yang bersifat paling kuat ke lemah berdasarkan nilai tetapan kesetimbangan asam adalah ....space 

  1. begin mathsize 14px style straight A greater than straight B greater than straight C end style  

  2. begin mathsize 14px style straight A greater than straight C greater than straight B end style 

  3. begin mathsize 14px style straight B greater than straight C greater than straight A end style 

  4. begin mathsize 14px style straight B greater than straight A greater than straight C end style 

  5. begin mathsize 14px style straight C greater than straight A greater than straight B end style 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

17

:

17

:

39

Klaim

Iklan

F. Juliano

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

jawaban yang benar adalah B.

Pembahasan

Pada asam lemah, tetapan kesetimbangan asam atau menyatakan rasio banyaknya jumlah ion yang terbentuk dibandingkan dengan molekul yang tidak terdisosiasi. Nilai makin besar, maka larutan makin asam. Nilai makin kecil, maka larutan kurang asam. Nilai pada masing-masing larutan dapat dihitung menggunakan persamaan: Larutan A Larutan B Larutan C Dengan demikian, berdasarkan nilai , urutan larutan asam yang bersifat paling kuat kelemah adalah atau . Jadi, jawaban yang benar adalah B.

Pada asam lemah, tetapan kesetimbangan asam atau begin mathsize 14px style straight K subscript straight a end style menyatakan rasio banyaknya jumlah ion begin mathsize 14px style H to the power of plus sign end style yang terbentuk dibandingkan dengan molekul yang tidak terdisosiasi. 

  • Nilai begin mathsize 14px style straight K subscript straight a end style makin besar, maka larutan makin asam. 
  • Nilai begin mathsize 14px style straight K subscript straight a end style makin kecil, maka larutan kurang asam. 


Nilai begin mathsize 14px style straight K subscript straight a end style pada masing-masing larutan dapat dihitung menggunakan persamaan: 
 

  • Larutan A


    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative space log space left square bracket straight H to the power of plus right square bracket end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell 10 to the power of negative pH end exponent equals 10 to the power of negative 3 minus log space 5 end exponent equals 5 cross times 10 to the power of negative 3 end exponent end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell square root of straight K subscript straight a cross times straight M subscript straight a end root end cell row cell left square bracket straight H to the power of plus right square bracket squared end cell equals cell straight K subscript straight a blank straight x blank straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell blank left square bracket straight H to the power of plus right square bracket squared over straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell blank left square bracket 5 cross times 10 to the power of negative 3 end exponent right square bracket squared over 1 equals 25 cross times 10 to the power of negative 6 end exponent end cell end table end style      


     
  • Larutan B


    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative space log space left square bracket straight H to the power of plus right square bracket end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell 10 to the power of negative pH end exponent equals 10 to the power of negative 3 minus log space 3 end exponent equals 3 cross times 10 to the power of negative 3 end exponent end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell square root of straight K subscript straight a cross times straight M subscript straight a end root end cell row cell left square bracket straight H to the power of plus right square bracket squared end cell equals cell straight K subscript straight a cross times straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell left square bracket straight H to the power of plus right square bracket squared over straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell left square bracket 3 cross times 10 to the power of negative 3 end exponent right square bracket squared over 1 equals 9 cross times 10 to the power of negative 6 end exponent end cell end table end style   
     

     
  • Larutan C


    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative space log space left square bracket straight H to the power of plus right square bracket end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell 10 to the power of negative pH end exponent equals 10 to the power of negative 3 minus log space 4 end exponent equals 4 cross times 10 to the power of negative 3 end exponent end cell row cell left square bracket straight H to the power of plus right square bracket end cell equals cell square root of straight K subscript straight a cross times straight M subscript straight a end root end cell row cell left square bracket straight H to the power of plus right square bracket squared end cell equals cell straight K subscript straight a cross times straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell left square bracket straight H to the power of plus right square bracket squared over straight M subscript straight a end cell row cell straight K subscript straight a end cell equals cell left square bracket 4 cross times 10 to the power of negative 3 end exponent right square bracket squared over 1 equals 16 cross times 10 to the power of negative 6 end exponent end cell end table end style   
     
     

Dengan demikian, berdasarkan nilai begin mathsize 14px style straight K subscript straight a end style, urutan larutan asam yang bersifat paling kuat ke lemah adalah begin mathsize 14px style 25 cross times 10 to the power of negative 9 end exponent greater than 16 cross times 10 to the power of negative 9 end exponent greater than 9 cross times 10 to the power of negative 9 end exponent end style atau begin mathsize 14px style straight A greater than straight C greater than straight B end style.  


Jadi, jawaban yang benar adalah B.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Sebanyak 10,56 gram asam organik dengan K a ​ = 1 , 5 × 1 0 − 5 dilarutkan dalam 200 mL air. Ternyata, asam tersebut memiliki pH yang sama dengan larutan 0,003 M HCl. Asam organik tersebut yang mungki...

9

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia